我正在尝试使用HeadFirst从java到C ++的策略模式的端口示例
#include "iostream" using namespace std;
class IFlyBehavior
{
public:
virtual void fly() = 0;
};
class FlyWithWings : public IFlyBehavior
{
public:
void fly() override
{
cout << "fly!";
}
};
class FlyNoWay : public IFlyBehavior
{
public:
void fly() override
{
cout << "no fly!";
}
};
class IQuackBehavior
{
public:
virtual void quack() = 0;
};
class Quack : public IQuackBehavior
{
public:
void quack() override
{
cout << "Quack!";
}
};
class Squeak : public IQuackBehavior
{
public:
void quack() override
{
cout << "Squeak!";
}
};
class MuteQuack : public IQuackBehavior
{
public:
void quack() override
{
cout << "Can't quack";
}
};
class Duck : public IFlyBehavior, IQuackBehavior
{
public:
FlyWithWings* fly_behavior;
Quack* quack_behavior;
void swim()
{
cout << "Swim!";
}
virtual void display() = 0;
void performQuack()
{
quack_behavior->quack();
}
void performFly()
{
fly_behavior->fly();
}
};
class MallardDuck : public Duck
{
public:
MallardDuck()
{
quack_behavior = new Quack();
fly_behavior = new FlyWithWings();
}
void display() override
{
cout << "Mallard!";
}
};
class RedheadDuck : public Duck
{
public:
void display() override
{
cout << "RedHead!";
}
};
class DecoyDuck : public Duck
{
public:
void display() override
{
cout << "DecoyDuck!";
}
};
class RubberDuck : Duck
{
public:
void display() override
{
cout << "RubberDuck!";
}
};
int main(int argc, char* argv[])
{
Duck* md = new MallardDuck;
md->performFly();
md->performFly();
return 0;
}
但是我收到了错误: 不允许使用E0322抽象类类型“MallardDuck”的对象:Duck d:\ Code \ CODE \ C ++ \ Duck \ Duck \ Source.cpp 119 看起来编译器看不到实现的类,为什么会发生这种情况?关于它的任何想法?我该怎么做?
答案 0 :(得分:6)
您无法实例化MallardDuck
,因为MallardDuck
是Duck
,据称可以实现IQuackBehavior
接口,但无法覆盖void Quack()
。同样的飞行行为。
我建议您不要试图&#34;翻译&#34; Java到C ++;它们是完全不同的语言,应该这样对待。 Here are some good books for learning the language you're actually using
答案 1 :(得分:0)
MallardDuck
继承了Duck
,它继承自抽象类IFlyBehavior
和IQuackBehavior
。但是没有地方覆盖那些抽象类中的抽象函数。
相反,你似乎有一个奇怪的混合继承与封装。