Question

我在JS中有以下对象：

[
  {
    "financial_year":1,
    "mainline_revenue":18743.0,
    "regional_revenue":2914.0,
    "other_revenue":3198.0,
    "non_operating_items":-1983.0
  },
  {
    "financial_year":2,
    "mainline_revenue":20218.0,
    "regional_revenue":3131.0,
    "other_revenue":3394.0,
    "non_operating_items":-3233.0
  },
  {
    "financial_year":3,
    "mainline_revenue":30802.0,
    "regional_revenue":6322.0,
    "other_revenue":5526.0,
    "non_operating_items":-1367.0
  }
]

financial_year 是我想用来过滤数据的唯一标识符。如何过滤数据，例如financial_year为2，并将其他值放在数组中？

Answer 1

您可以在数组上使用filter方法。 filter采用返回true或false的回调（更准确地说，是真值或假值）。如果返回true，则该对象包含在结果数组中。

＆＃13;

let input = [
  {
    "financial_year":1,
    "mainline_revenue":18743.0,
    "regional_revenue":2914.0,
    "other_revenue":3198.0,
    "non_operating_items":-1983.0
  },
  {
    "financial_year":2,
    "mainline_revenue":20218.0,
    "regional_revenue":3131.0,
    "other_revenue":3394.0,
    "non_operating_items":-3233.0
  },
  {
    "financial_year":3,
    "mainline_revenue":30802.0,
    "regional_revenue":6322.0,
    "other_revenue":5526.0,
    "non_operating_items":-1367.0
  }
];
let output = input.filter((obj) => obj.financial_year !== 2);
console.log(JSON.stringify(output, null, 2));

＆＃13;

或用ES5重写：

＆＃13;

var input = [
  {
    "financial_year":1,
    "mainline_revenue":18743.0,
    "regional_revenue":2914.0,
    "other_revenue":3198.0,
    "non_operating_items":-1983.0
  },
  {
    "financial_year":2,
    "mainline_revenue":20218.0,
    "regional_revenue":3131.0,
    "other_revenue":3394.0,
    "non_operating_items":-3233.0
  },
  {
    "financial_year":3,
    "mainline_revenue":30802.0,
    "regional_revenue":6322.0,
    "other_revenue":5526.0,
    "non_operating_items":-1367.0
  }
];
var output = input.filter(function(obj) {
  return obj.financial_year !== 2;
});
console.log(JSON.stringify(output, null, 2));

＆＃13;

JavaScript：如何过滤字典中的数据

1 个答案: