说我有一个过滤器:
filter = [ {key: "pl", value: 3}, {key: "sh", value: 2} ]
我想使用上述过滤条件过滤以下javascript对象:
var data = [
{title: "The Uncertainty of the Poet ",
pl: 3,
si: 2,
va: 3,
te: 0,
co: 0,
or: 4,
sh: 2,
po: 0,
li: 0,
ar: 5
},
{
title: "Direction",
pl: 4,
si: 3,
va: 1,
te: 3,
co: 0,
or: 3,
sh: 2,
po: 0,
li: 0,
ar: 5
}
...
]
我没有运气就尝试了以下方法:
var result = data.filter(function(d){
for (item in filter) {
return d.key==d.value;
}
答案 0 :(得分:1)
检查对象是否符合所有条件的另一个可能选择:
data.filter(function(obj) {
return filter.reduce(function(a, f) {
return a && (obj[f.key] === f.value);
}, true);
});
由于使用了reduce,因此无需检查hasOwnProperty就可以工作。如果要检查是否有任何过滤条件成立,则可以将其更改为
data.filter(function(obj) {
return filter.reduce(function(a, f) {
return a || (obj[f.key] === f.value);
}, false);
});
答案 1 :(得分:0)
您对[{ "id":"1", "subject_id":"2", "questionaire_id":"1", "name":"Quiz 1", "description":"Answer this quiz within 1 hour", "start":"7:30AM", "end":"8:30AM", "date":"08-01-18", "questionaire_name":"Right triangle", "questionaire_description":"Questionaire # 1" }]
的了解不够深。它正在遍历数组,并且无法处理数组中的每个对象
可以使用Array#every()
来确保过滤器数组中的每个对象在数据对象中都匹配
for in
// filter main data
var result = data.filter(function(dataObj){
// check if all proprties within filter array are a match
return filter.every(function(filterObj){
//compare value of property found in filterObject with value
return dataObj[filterObj.key] === filterObj.value
})
})
console.log(result)
答案 2 :(得分:0)
如果您希望它匹配一个或另一个值,这将起作用:
match = [ {key: "pl", value: 3}, {key: "sh", value: 2} ]
var result = data.filter(function(d) {
return d.pl === match[0]['value'] || d.sh === match[1]['value']
})
为避免混淆,我将数组的名称更改为match
。
答案 3 :(得分:0)
您也可以这样做:
var filters = [{key: "pl", value: 3}, {key: "sh", value: 2}]
var data = [
{
title: "The Uncertainty of the Poet ",
pl: 2,
si: 2,
va: 3,
te: 0,
co: 0,
or: 4,
sh: 3,
po: 0,
li: 0,
ar: 5
},
{
title: "Direction",
pl: 3,
si: 3,
va: 1,
te: 3,
co: 0,
or: 3,
sh: 2,
po: 0,
li: 0,
ar: 5
}
]
var result = data.filter((item) => {
for(let i = 0; i < filters.length; ++i) {
let filter = filters[i];
if(item[filter.key] && item[filter.key] === filter.value) {
return true;
}
}
return false;
});