我创造了一个简单的游戏而且我遇到了问题。
游戏是这样的: "白方"吃绿色广场"
问题:
我怎样才能产生新的红色方块"每次"白方"并留在屏幕上吃一个"绿色广场" ?
以下是代码:
import pygame, sys
from random import randint
from pygame.locals import*
pygame.init()
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption("Square-it")
clock = pygame.time.Clock()
"Green Square"
green_x = randint(10, 780)
green_y = randint(10, 580)
green_width = 15
green_height = 15
green_color = pygame.Color("green")
green = pygame.Rect(green_x, green_y, green_width, green_height)
"Red Square"
red_x = randint(20, 780)
red_y = randint(20, 580)
red_width = 10
red_height = 10
red_color = pygame.Color("red")
red = pygame.Rect(red_x, red_y, red_width, red_height)
"White Square"
white_x = 400
white_y = 300
white_width = 10
white_height = 10
white_color = pygame.Color("white")
white = pygame.Rect(white_x, white_y, white_width, white_height)
while True:
clock.tick(60)
gameDisplay.fill((0, 20, 5))
gameDisplay.fill(white_color, white)
gameDisplay.fill(green_color, green)
gameDisplay.fill(red_color, red)
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
'''When White eats Green, Green regenerates'''
if white.colliderect(green):
green = pygame.Rect(randint(10, 780), randint(10, 580), green_width, green_height)
'''White Square Movement'''
keys = pygame.key.get_pressed()
if keys[K_LEFT]:
white.left = white.left - 10
if keys[K_RIGHT]:
white.right = white.right + 10
if keys[K_UP]:
white.top = white.top - 10
if keys[K_DOWN]:
white.bottom = white.bottom + 10
答案 0 :(得分:0)
首先应创建一个数组来存储所有红色矩形实例
red_square_list = []
当你的白色矩形碰撞绿色矩形时,你应该提取绿色矩形的x,y位置,并在这个位置创建一个红色矩形的实例。
要做到这一点,我建议使用类,但首先你可以创建一个函数来创建一个红色矩形:
def create_red_square(x, y)
red_width = 10
red_height = 10
red_color = pygame.Color("red")
red = pygame.Rect(red_x, red_y, red_width, red_height)
return red
现在,每当白色碰撞绿色时,您必须提取绿色矩形位置并使用上述功能显示红色矩形位置:
if white.colliderect(green):
pos_x, pos_y = green.left, green.top
green = pygame.Rect(randint(10, 780), randint(10, 580), green_width, green_height)
red_square_list.append(create_red_square(pos_x, pos_y))
最后一行只是为了存储红色矩形,如果你想稍后使用它们(就像你对绿色/白色矩形一样)
我希望它有所帮助,
编辑#1:
我犯了一些小错误就是以前的代码,这是一个有效的解决方案:
` import pygame,sys 来自随机导入randint 来自pygame.locals import *
red_square_list = []
pygame.init()
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption("Square-it")
clock = pygame.time.Clock()
red_color = pygame.Color("red")
"Green Square"
green_x = randint(10, 780)
green_y = randint(10, 580)
green_width = 15
green_height = 15
green_color = pygame.Color("green")
green = pygame.Rect(green_x, green_y, green_width, green_height)
def create_red_square(x, y):
"""Return one instance of Rect at position x, y"""
red_width = 10
red_height = 10
red = pygame.Rect(x, y, red_width, red_height)
return red
"White Square"
white_x = 400
white_y = 300
white_width = 10
white_height = 10
white_color = pygame.Color("white")
white = pygame.Rect(white_x, white_y, white_width, white_height)
while True:
clock.tick(60)
gameDisplay.fill((0, 20, 5))
gameDisplay.fill(white_color, white)
gameDisplay.fill(green_color, green)
for each in red_square_list: #display all red rect
gameDisplay.fill(red_color, each)
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
'''When White eats Green, Green regenerates'''
if white.colliderect(green):
# extract green rect position
pos_left, pos_top = green.left, green.top
# store the new red rectangle in the array
red_square_list.append(create_red_square(pos_left+2, pos_top+2))
# +2 is required as red square are 10x10 and green 15x15
# new rect green
new_left = randint(10, 780)
new_top = randint(10, 580)
green = pygame.Rect(new_left, new_top, green_width, green_height)
'''White Square Movement'''
keys = pygame.key.get_pressed()
if keys[K_LEFT]:
white.left = white.left - 10
if keys[K_RIGHT]:
white.right = white.right + 10
if keys[K_UP]:
white.top = white.top - 10
if keys[K_DOWN]:
white.bottom = white.bottom + 10
我希望它有所帮助,