我构建了一个允许用户上传文件的应用。 另一方面, 我有一些python脚本,它接受一个文本文件,将其转换为CSV并做pandas。在终端中运行时,此脚本可以正常运行。 现在我想将这个python脚本应用到Django中的文件上传中,并在httpResponse中显示该文件并可以下载它。
import csv
import pandas as pd
df = pd.read_csv('raw_df.txt', delimiter = '\t' , usecols=['Sample','Cohort','Metabolite Name','Intensity'])
df = df[df['Cohort'].str.contains("std")]
df = df.groupby(['Cohort', 'Metabolite Name'])['Intensity'].sum().reset_index()
df = df[['Cohort','Intensity']]
c = 'Cohort'
s = df.set_index([c, df.groupby(c).cumcount() + 2]).Intensity
df = s.unstack().add_prefix('Intensity').reset_index()
df.to_csv()
print df;
views.py
from django.shortcuts import render, redirect
from django.conf import settings
from django.core.files.storage import FileSystemStorage
from uploads.core.models import Document
from uploads.core.forms import DocumentForm
def home(request):
documents = Document.objects.all()
return render(request, 'core/home.html', { 'documents': documents })
def model_form_upload(request):
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
form.save()
return redirect('home')
else:
form = DocumentForm()
return render(request, 'core/model_form_upload.html', {
'form': form
})
Models.py
class Document(models.Model):
document = models.FileField(upload_to='documents/')
模板上传页面
{% extends 'base.html' %}
{% block content %}
<form method="post" enctype="multipart/form-data">
{% csrf_token %}
{{ form.as_p }}
<button type="submit">Upload</button>
</form>
<p><a href="{% url 'home' %}">Return to home</a></p>
{% endblock %}
答案 0 :(得分:0)
使用方法包装文件处理:
import csv
import pandas as pd
def process_file(file_handle):
df = pd.read_csv(file_handle, delimiter = '\t' , usecols['Sample','Cohort','Metabolite Name','Intensity'])
df = df[df['Cohort'].str.contains("std")]
df = df.groupby(['Cohort', 'Metabolite Name'])['Intensity'].sum().reset_index()
df = df[['Cohort','Intensity']]
c = 'Cohort'
s = df.set_index([c, df.groupby(c).cumcount() + 2]).Intensity
df = s.unstack().add_prefix('Intensity').reset_index()
return df.to_csv()
在您的观点中:
...
if form.is_valid():
document = form.save()
# call to the new method
csv = process_file(document.document)
response = HttpResponse(csv, content_type='text/csv')
response['Content-Disposition'] = 'attachment; filename=result.csv'
return response
...