非常感谢有人可以帮我解决这里的语法 - 我希望每次都能获得一些不同的文本文件。这是我的代码的一般结构。如何依次获取每个文件(f0,f1和f2)?
window.onload = function(){
var f = (function(){
var xhr = [];
for (i = 0; i < 3; i++){
(function (i){
xhr[i] = new XMLHttpRequest();
f0 = "0.txt"
f1 = "1.txt"
f2 = "2.txt"
//??? xhr[i].open("GET", file i, true);
xhr[i].onreadystatechange = function () {
if (xhr[i].readyState == 4 && xhr[i].status == 200) {
//do stuff
}
};
xhr[i].send();
})(i);
}
})();
};
答案 0 :(得分:1)
只需将文件名放在数组中即可。
window.onload = function(){
var f = (function(){
var xhr = [];
var files = ["f0.txt", "f1.txt", "f2.txt"];
for (i = 0; i < 3; i++){
(function (i){
xhr[i] = new XMLHttpRequest();
xhr[i].open("GET", files[i], true);
xhr[i].onreadystatechange = function () {
if (xhr[i].readyState == 4 && xhr[i].status == 200) {
//do stuff
}
};
xhr[i].send();
})(i);
}
})();
};
答案 1 :(得分:0)
这样的事情应该有效
// ...
for (i = 0; i < 3; i++){
(function (i){
xhr[i] = new XMLHttpRequest();
xhr[i].open('GET', i.toString() + '.txt'); // <-- this line
xhr[i].onreadystatechange = function () {
if (xhr[i].readyState == 4 && xhr[i].status == 200) {
// ....