Question

首先，我有这个图像，我想创建一个可以检测像这样的图像并从中删除圆圈（水印）的应用程序。

int main(){
    Mat im1,im2,im3,gray,gray2,result;

    im2=imread(" (2).jpg");
    namedWindow("x",CV_WINDOW_FREERATIO);
    imshow("x",im2);

    //converting it to gray
    cvtColor(im2,gray,CV_BGR2GRAY);
    // creating a new image that will have the cropped ellipse
    Mat ElipseImg(im2.rows,im2.cols,CV_8UC1,Scalar(0,0,0));

    //detecting the largest circle
    GaussianBlur(gray,gray,Size(5,5),0);
    vector<Vec3f> circles;
    HoughCircles(gray,circles,CV_HOUGH_GRADIENT,1,gray.rows/8,100,100,100,0);

    uchar x;
    int measure=0;int id=0;
    for(int i=0;i<circles.size();i++){
        if(cvRound(circles[i][2])>measure && cvRound(circles[i][2])<1000){
            measure=cvRound(circles[i][2]);
            id=i;
        }
    }


    Point center(cvRound(circles[id][0]),cvRound(circles[id][1]));
    int radius=cvRound(circles[id][2]);
    circle(im2,center,3,Scalar(0,255,0),-1,8,0);
    circle(im2,center,radius,Scalar(0,255,0),2,8,0);
    ellipse(ElipseImg,center,Size(radius,radius),0,0,360,Scalar(255,255,255),-1,8);
    cout<<"center: "<<center<<" radius: "<<radius<<endl;



    Mat res;
    bitwise_and(gray,ElipseImg,result);
    namedWindow("bitwise and",CV_WINDOW_FREERATIO);
    imshow("bitwise and",result);

    // trying to estimate the Intensity  of the circle for the thresholding
    x=result.at<uchar>(cvRound(circles[id][0]+30),cvRound(circles[id][1]));
    cout<<(int)x;

    //thresholding the  output image
    threshold(ElipseImg,ElipseImg,(int)x-10,250,CV_THRESH_BINARY);
    namedWindow("threshold",CV_WINDOW_FREERATIO);
    imshow("threshold",ElipseImg);

    // making bitwise_or
    bitwise_or(gray,ElipseImg,res);
    namedWindow("bitwise or",CV_WINDOW_FREERATIO);
    imshow("bitwise or",res);

    waitKey(0);
}

到目前为止，我所做的是：

我将其转换为灰度
我使用霍夫圆圈检测到最大的圆圈，然后在新图像中创建一个半径相同的圆圈
使用（bitwise_and）灰度的新圆圈为我提供仅包含该圆圈的图像
新图像的阈值
bitwise_or阈值的结果

我的问题是，这个圆圈内的弯曲白线上的任何黑色文字都没有出现。我试图通过使用像素值而不是阈值来删除颜色，但问题是否相同所以任何解决方案或建议？

结果如下：

Answer 1

我不确定您的情况下是否可接受以下解决方案。但我认为它表现稍好一些，并不关心水印的形状。

使用形态滤波删除笔划。这应该给你一个背景图片。
计算差异图像：差异=背景 - 初始，阈值：二进制=阈值（差异）

阈值背景图像并提取水印覆盖的暗区

从初始图像中提取水印区域内的像素并对这些像素进行阈值处理，然后将其粘贴到较早的二进制图像

以上是粗略的描述。下面的代码应该更好地解释它。

Mat im = [load the color image here];

Mat gr, bg, bw, dark;

cvtColor(im, gr, CV_BGR2GRAY);

// approximate the background
bg = gr.clone();
for (int r = 1; r < 5; r++)
{
    Mat kernel2 = getStructuringElement(MORPH_ELLIPSE, Size(2*r+1, 2*r+1));
    morphologyEx(bg, bg, CV_MOP_CLOSE, kernel2);
    morphologyEx(bg, bg, CV_MOP_OPEN, kernel2);
}

// difference = background - initial
Mat dif = bg - gr;
// threshold the difference image so we get dark letters
threshold(dif, bw, 0, 255, CV_THRESH_BINARY_INV | CV_THRESH_OTSU);
// threshold the background image so we get dark region
threshold(bg, dark, 0, 255, CV_THRESH_BINARY_INV | CV_THRESH_OTSU);

// extract pixels in the dark region
vector<unsigned char> darkpix(countNonZero(dark));
int index = 0;
for (int r = 0; r < dark.rows; r++)
{
    for (int c = 0; c < dark.cols; c++)
    {
        if (dark.at<unsigned char>(r, c))
        {
            darkpix[index++] = gr.at<unsigned char>(r, c);
        }
    }
}
// threshold the dark region so we get the darker pixels inside it
threshold(darkpix, darkpix, 0, 255, CV_THRESH_BINARY | CV_THRESH_OTSU);

// paste the extracted darker pixels
index = 0;
for (int r = 0; r < dark.rows; r++)
{
    for (int c = 0; c < dark.cols; c++)
    {
        if (dark.at<unsigned char>(r, c))
        {
            bw.at<unsigned char>(r, c) = darkpix[index++];
        }
    }
}

Answer 2

dhanushka的answer 的Python版本

# Import the necessary packages
import cv2
import numpy as np


def back_rm(filename):
    # Load the image
    img = cv2.imread(filename)

    # Convert the image to grayscale
    gr = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)

    # Make a copy of the grayscale image
    bg = gr.copy()

    # Apply morphological transformations
    for i in range(5):
        kernel2 = cv2.getStructuringElement(cv2.MORPH_ELLIPSE,
                                            (2 * i + 1, 2 * i + 1))
        bg = cv2.morphologyEx(bg, cv2.MORPH_CLOSE, kernel2)
        bg = cv2.morphologyEx(bg, cv2.MORPH_OPEN, kernel2)

    # Subtract the grayscale image from its processed copy
    dif = cv2.subtract(bg, gr)

    # Apply thresholding
    bw = cv2.threshold(dif, 0, 255, cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]
    dark = cv2.threshold(bg, 0, 255, cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)[1]

    # Extract pixels in the dark region
    darkpix = gr[np.where(dark > 0)]

    # Threshold the dark region to get the darker pixels inside it
    darkpix = cv2.threshold(darkpix, 0, 255, cv2.THRESH_BINARY | cv2.THRESH_OTSU)[1]

    # Paste the extracted darker pixels in the watermark region
    bw[np.where(dark > 0)] = darkpix.T

    cv2.imwrite('final.jpg', bw)


back_rm('watermark.jpg')

这是最终结果：
使用numpy

的处理时间非常短

time python back_rm.py 

real    0m0.391s
user    0m0.518s
sys     0m0.185s

使用opencv从图像中删除水印

2 个答案: