我正在使用基本类并尝试访问成员函数中的成员字符串数组。我很困惑因为如果我只调用set_words
,print_words
和del_words
函数,字符串数组会初始化并释放而没有任何内存错误(Dr. Memory):
class XWORD {
public:
int vdir;
int len;
int wid;
int nWords;
char ** arr;
char ** words;
...
};
void XWORD::set_words(int istart, int inWords, char* iwords[]) {
int w = istart;
int k = 0;
this->nWords = inWords;
this->words = new char* [this->nWords];
for (w=istart; w<(istart+this->nWords); w++) {
this->words[k] = new char [1+strlen(iwords[w])];
this->words[k] = strcpy(this->words[k], iwords[w]);
k++;
}
}
void XWORD::del_words() {
int w = 0;
for (w=0; w<(this->nWords); w++) {
delete[] this->words[w];
}
delete[] this->words;
}
void XWORD::print_words() {
int w = 0;
for (w=0; w<(this->nWords); w++) {
printf("\n%s",this->words[w]);
}
printf("\n");
}
但是,当我调用以下函数时,我得到下面显示的Dr.内存错误(init_arr
和del_arr
单独也不会出错):
void XWORD::add_word_to_arr(int iw, int iy, int ix) {
int k = 0;
int y = iy;
int x = ix;
for (k=0; k<(int)strlen(this->words[iw]); k++) {
this->arr[y][x] = this->words[iw][k];
if (this->vdir) {
y++;
} else {
x++;
}
}
}
int main(int argc, char * argv[]) {
XWORD x;
x.set_words(1, argc-1, argv);
x.init_arr(10,10);
x.add_word_to_arr(0, x.len/2, x.wid/2); // WITHOUT THIS, NO ERRORS
x.print_words();
x.del_words();
x.del_arr();
}
博士。内存错误:
c:\MinGW\WORKSPACE\cpp\xword>make runmem
drmemory -brief -batch bin/test.exe
~~Dr.M~~ Dr. Memory version 1.8.0
~~Dr.M~~ Running "bin/test.exe"
~~Dr.M~~
~~Dr.M~~ Error #1: UNADDRESSABLE ACCESS beyond heap bounds: reading 4 byte(s)
~~Dr.M~~ # 0 XWORD::add_word_to_arr [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:301]
~~Dr.M~~ # 1 main [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:302]
~~Dr.M~~ Note: refers to 0 byte(s) beyond last valid byte in prior malloc
~~Dr.M~~
~~Dr.M~~ Error #2: UNADDRESSABLE ACCESS: reading 1 byte(s)
~~Dr.M~~ # 0 replace_strlen [d:\drmemory_package\drmemory\replace.c:375]
~~Dr.M~~ # 1 XWORD::add_word_to_arr [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:301]
~~Dr.M~~ # 2 main [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:302]
~~Dr.M~~
~~Dr.M~~ Error #3: LEAK 0 bytes
~~Dr.M~~ # 0 replace_operator_new_array [d:\drmemory_package\common\alloc_replace.c:2638]
~~Dr.M~~ # 1 XWORD::set_words [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:301]
~~Dr.M~~ # 2 main [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:302]
~~Dr.M~~
~~Dr.M~~ Error #4: LEAK 40 direct bytes + 110 indirect bytes
~~Dr.M~~ # 0 replace_operator_new_array [d:\drmemory_package\common\alloc_replace.c:2638]
~~Dr.M~~ # 1 XWORD::init_arr [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:301]
~~Dr.M~~ # 2 main [../mingwrt-4.0.3-1-mingw32-src/src/libcrt/crt/crt1.c:302]
~~Dr.M~~
~~Dr.M~~ ERRORS FOUND:
~~Dr.M~~ 2 unique, 2 total unaddressable access(es)
~~Dr.M~~ 0 unique, 0 total uninitialized access(es)
~~Dr.M~~ 0 unique, 0 total invalid heap argument(s)
~~Dr.M~~ 0 unique, 0 total GDI usage error(s)
~~Dr.M~~ 0 unique, 0 total handle leak(s)
~~Dr.M~~ 0 unique, 0 total warning(s)
~~Dr.M~~ 2 unique, 2 total, 150 byte(s) of leak(s)
~~Dr.M~~ 0 unique, 0 total, 0 byte(s) of possible leak(s)
~~Dr.M~~ Details: C:\Users\jesse\AppData\Roaming\Dr. Memory\DrMemory-test.exe.4512.000\results.txt
~~Dr.M~~ WARNING: application exited with abnormal code 0xc0000005
make: *** [runmem] Error 5
另外,当我在this->words[0]
函数中打印add_word_to_arr
的“%s”时,它是null
。然而,它可以从print_words();
打印出来。
exe调用是:
bin\test.exe a123 b123
init_arr()
是:
void XWORD::init_arr(int ilen, int iwid) {
int y = 0;
int x = 0;
this->len = ilen;
this->wid = iwid;
this->arr = new char* [this->len];
for (y=0; y<(this->len); y++) {
this->arr[y] = new char [1+this->wid];
for (x=0; x<(this->wid); x++) {
this->arr[y][x] = BLANK;
}
this->arr[y][x] = (char) NULL;
}
}
答案 0 :(得分:0)
Ok init_arr(10,10)
初始化一个10个大小为11的char数组的数组(10个字符+ 1个终止空值)。
然后,调用add_word_to_arr(0, 5, 5)
,以便将第一个单词(命令行的第一个参数)复制到从位置5,5开始的数组中。因此,如果该字至少为7个字符且vdir == 0或6与vdir!= 0,则写入保留的数组。我可以使用params“foo”和“bar”成功运行,但不能使用“feefoobar”。
您应该计算最长单词的长度,并在调用int_arr
无论如何,它看起来你测试vdir
值而不在任何地方初始化它。这会导致未定义的行为,因为您无法知道将遵循哪个分支(水平或垂直),并且您真的应该以这种方式重写add_word_to_arr
:
void XWORD::add_word_to_arr(int iw, int iy, int ix) {
int k = 0;
int y = iy;
int x = ix;
for (k=0; k<(int)strlen(this->words[iw]); k++) {
this->arr[y][x] = this->words[iw][k];
if (this->vdir) {
if (++y >= this.len) return; // refuse to write past allocated mem
} else {
if (++x > this.wid) return; // refuse to write past allocated mem
}
}
}
我在强制vdir值一次为0并且一次为1之后在调试器下执行它,它从未访问过去分配的内存。但我不得不想象一些代码,因为你没有给出Minimal Compilable Verifiable example
答案 1 :(得分:0)
原来我正在使用我的makefile
运行我的Dr. Memory工具,忘了将$(ARGS)
包含在我的make runmem
目标中:
FLAGS = -Wall -std=c++11 -pedantic
LIBS = -Iinclude
SRC = src/xword.cpp
TGT = bin/test.exe
ARGS = human prothean vorcha krogan asari salarian turian batarian quarian
all:
g++ $(SRC) -o $(TGT) $(FLAGS) $(LIBS)
run:
$(TGT) $(ARGS)
runmem:
drmemory -batch $(TGT) **$(ARGS)** # was missing
这就是Dr.Memory封装执行期间argv
为空的原因,以及为什么代码只会在这些执行期间崩溃。
在此处向$(ARGS)
添加makefile
后,没有任何内容崩溃,也没有报告任何错误/泄漏。
对于鹅追逐感到抱歉,感谢您的帮助 - 如果这是一个应该删除的冗余帖子,请告诉我。