我需要将Spring Security与自定义登录页面和数据库连接添加到我的Spring MVC项目中。我收到以下错误消息,根据其他问题的答案,我试图更改代码,例如我将我的Spring Security Schema版本更改为4.0但代码返回以下错误:
将架构更改为4.0
http://www.springframework.org/schema/security/spring-security-4.0.xsd
错误
Cannot initialize context because there is already a root application context
present - check whether you have multiple ContextLoader* definitions in your
web.xml!
我的代码
我-security.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns='http://www.springframework.org/schema/security'
xmlns:beans='http://www.springframework.org/schema/beans' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'
xsi:schemaLocation='http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd'>
<beans:import resource="security-db.xml" />
<http auto-config="true" access-denied-page="/notFound.jsp"
use-expressions="true">
<intercept-url pattern="/" access="permitAll" />
</http>
</beans:beans>
的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<listener>
<listener-class>org.apache.tiles.extras.complete.CompleteAutoloadTilesListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>my</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>my</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/my-security.xml
</param-value>
</context-param>
</web-app>
安全-db.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost/dbproj" />
<property name="username" value="jack" />
<property name="password" value="jack" />
</bean>
</beans>
答案 0 :(得分:5)
我认为您只需要一个xml配置文件(my-servlet.xml,因为 servlet名称是“my”所以文件名必须是“ my-servlet.xml “)在web-xml中,然后引用该文件中的其他人。请参阅下面的xmls。
<xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<listener>
<listener-class>org.apache.tiles.extras.complete.CompleteAutoloadTilesListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>my</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/my-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
</web-app>
在my-servlet.xml文件中,您可以使用import来组成其他XML配置。
<beans>
<bean id="bean1" class="..."/>
<bean id="bean2" class="..."/>
<import resource="security-db.xml"/>
<import resource="foo-db.xml"/>
</beans>
答案 1 :(得分:4)
将$password = 'passwod';
$outfile = 'download.zip';
$infile = 'pic1.jpg';
header("Content-type: application/octet-stream");
header("Content-disposition: attachment; filename=$outfile");
@system("zip -P $password $outfile $infile");
readfile($outfile);
@unlink($outfile);
添加到您的web.xml:
DelegatingFilterProxy
将<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>my</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>my</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:config/security-config.xml</param-value>
</context-param>
</web-app>
添加为my-servlet.xml
的Web应用程序上下文配置。
将/webapp/WEB-INF/
元素添加到authentication-manager
:
my-security.xml
摆脱<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<beans:import resource="spring-db.xml" />
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/" access="permitAll" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="username" authorities="ROLE_ADMIN" password="password" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
并使用access-denied-page
作为Mkyong did it here