Question

我有这个查询，它将搜索一些新闻并将新闻数据作为其组，公司和类别返回。事情是一个新闻可以有很多公司和组，我需要在每个字段中连接这个结果（grupoNome和empresaNome），所以使这个查询只返回一行：

这是我的“正常”查询结果：

id  titulo  categoriaId url     categoriaNome       grupoNome   empresaNome
5   Teste   1           teste   "Todas as Notícas"  "Group 1"   Company 1
5   Teste   1           teste   "Todas as Notícas"  "Group 1"   Company 2
5   Teste   1           teste   "Todas as Notícas"  "Group 1"   Company 3
5   Teste   1           teste   "Todas as Notícas"  "Group 1"   Company 4
5   Teste   1           teste   "Todas as Notícas"  "Group 2"   Company 1
5   Teste   1           teste   "Todas as Notícas"  "Group 2"   Company 2
5   Teste   1           teste   "Todas as Notícas"  "Group 2"   Company 3
5   Teste   1           teste   "Todas as Notícas"  "Group 2"   Company 4
5   Teste   1           teste   "Todas as Notícas"  "Group 3"   Company 1
5   Teste   1           teste   "Todas as Notícas"  "Group 3"   Company 2
5   Teste   1           teste   "Todas as Notícas"  "Group 3"   Company 3
5   Teste   1           teste   "Todas as Notícas"  "Group 3"   Company 4

这是我的疑问：

SELECT n.*, nc.nome AS categoriaNome, g.nome AS grupoNome, e.nome AS empresaNome FROM `noticias` n
INNER JOIN `noticiascategorias` nc ON n.categoriaId = nc.id
INNER JOIN `noticiasgrupos` ng ON n.id = ng.noticiaId
INNER JOIN `grupos` g ON g.id = ng.grupoId
INNER JOIN `noticiasempresas` ne ON n.id = ne.noticiaId
INNER JOIN `empresas` e ON e.id = ne.empresaId
WHERE n.url LIKE 'teste';

noticiasgrupos / noticiasempresas包含新闻和群组/公司的多对多关系。

grupos / empresas包含群组/公司信息。

编辑：

我需要结果如下：

5   Teste   1   teste   "Todas as Notícas"  "Group 1_Group2_Group_3" "Company 1_Company_Company_3"

除数可以是我以后可以用来拆分的任何东西（| _ *）

Answer 1

您可以使用GROUP_CONCAT执行此操作。只需将GROUP BY设置为您想要分组的内容即可。您也可以为GROUP_CONCAT指定排序顺序和分隔符。

SELECT n.*, nc.nome AS categoriaNome, 
       GROUP_CONCAT(DISTINCT g.nome ORDER BY g.nome ASC SEPARATOR '_' ) AS grupoNome,
       GROUP_CONCAT(DISTINCT e.nome ORDER BY g.nome ASC SEPARATOR '_' ) AS EmpresaNome
FROM `noticias` n
INNER JOIN `noticiascategorias` nc ON n.categoriaId = nc.id
INNER JOIN `noticiasgrupos` ng ON n.id = ng.noticiaId
INNER JOIN `grupos` g ON g.id = ng.grupoId
INNER JOIN `noticiasempresas` ne ON n.id = ne.noticiaId
INNER JOIN `empresas` e ON e.id = ne.empresaId
WHERE n.url LIKE 'teste'
GROUP BY n.id;

连接MySql结果

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