我正在尝试执行查询并将结果附加到另一个查询结果中，以维护顺序。所以我用“假变量”计算距离并在最后排序，然后按距离计算。
以下是查询：
-- --------------------------------------------------------------------------------
-- Routine DDL
-- Note: comments before and after the routine body will not be stored by the server
-- --------------------------------------------------------------------------------
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `Test`(IN basic_user_id INT, IN max_dist INT, IN q VARCHAR(255), IN index_start INT, IN index_end INT)
BEGIN
DECLARE mylon DOUBLE;
DECLARE mylat DOUBLE;
DECLARE lon1 FLOAT;
DECLARE lon2 FLOAT;
DECLARE lat1 FLOAT;
DECLARE lat2 FLOAT;
SET @location_id = (SELECT location_id from basicuser where id = basic_user_id);
SET @group_id = (SELECT group_id from basicuser where id = basic_user_id);
SET @subgroup_id = (SELECT subgroup_id from basicuser where id = basic_user_id);
SET @tertiarygroup_id = (SELECT tertiarygroup_id from basicuser where id = basic_user_id);
-- get the original lon and lat for the userid
SELECT longitude, latitude into mylon, mylat from location where id = @location_id;
set lon1 = mylon - max_dist / abs(cos(radians(mylat)) * 69);
set lon2 = mylon + max_dist / abs(cos(radians(mylat)) * 69);
set lat1 = mylat - (max_dist / 69);
set lat2 = mylat + (max_dist / 69);
select @group_id, @subgroup_id, @tertiarygroup_id;
(
SELECT 1 as `temp`, `inradar_ad`.*, 3956 * 2 * ASIN(SQRT(POWER(SIN((orig.latitude - dest.latitude) * pi()/180 / 2), 2) + COS(orig.latitude * pi()/180) * COS(dest.latitude * pi()/180) * POWER(SIN((orig.longitude - dest.longitude) * pi()/180 / 2), 2))) as distance
FROM
location AS dest
LEFT OUTER JOIN `inradar_ad` ON (`inradar_ad`.location_id = dest.id)
LEFT OUTER JOIN `inradar_ad_company` ON (`inradar_ad`.`id` = `inradar_ad_company`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_ad_person` ON (`inradar_ad`.`id` = `inradar_ad_person`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_category` ON (`inradar_ad`.`category_id` = `inradar_category`.`id`)
LEFT OUTER JOIN `inradar_subcategory` ON (`inradar_ad`.`subcategory_id` = `inradar_subcategory`.`id`)
LEFT OUTER JOIN `basicuser` ON (`inradar_ad`.`owner_id` = `basicuser`.`id`)
LEFT OUTER JOIN `auth_user` ON (`basicuser`.`user_id` = `auth_user`.`id`)
LEFT OUTER JOIN `inradar_ad_multiple` ON (`inradar_ad`.`multiple_advertiser_id` = `inradar_ad_multiple`.`id`),
location AS orig
WHERE orig.id = @location_id AND
(
(
`inradar_ad_multiple`.`id` IS NULL AND
(
`inradar_ad_company`.`corporate_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad_person`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_category`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_subcategory`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad`.`description` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`first_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`last_name` LIKE REPLACE('%$$**$$%', '$$**$$', q)
)
)
) AND
`basicuser`.`tertiarygroup_id` = @tertiarygroup_id AND
dest.longitude BETWEEN lon1 AND lon2 AND dest.latitude BETWEEN lat1 AND lat2
HAVING distance < max_dist
) UNION (
SELECT 2 as `temp`, `inradar_ad`.*, 3956 * 2 * ASIN(SQRT(POWER(SIN((orig.latitude - dest.latitude) * pi()/180 / 2), 2) + COS(orig.latitude * pi()/180) * COS(dest.latitude * pi()/180) * POWER(SIN((orig.longitude - dest.longitude) * pi()/180 / 2), 2))) as distance
FROM
location AS dest
LEFT OUTER JOIN `inradar_ad` ON (`inradar_ad`.location_id = dest.id)
LEFT OUTER JOIN `inradar_ad_company` ON (`inradar_ad`.`id` = `inradar_ad_company`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_ad_person` ON (`inradar_ad`.`id` = `inradar_ad_person`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_category` ON (`inradar_ad`.`category_id` = `inradar_category`.`id`)
LEFT OUTER JOIN `inradar_subcategory` ON (`inradar_ad`.`subcategory_id` = `inradar_subcategory`.`id`)
LEFT OUTER JOIN `basicuser` ON (`inradar_ad`.`owner_id` = `basicuser`.`id`)
LEFT OUTER JOIN `auth_user` ON (`basicuser`.`user_id` = `auth_user`.`id`)
LEFT OUTER JOIN `inradar_ad_multiple` ON (`inradar_ad`.`multiple_advertiser_id` = `inradar_ad_multiple`.`id`),
location AS orig
WHERE orig.id = @location_id AND
(
(
`inradar_ad_multiple`.`id` IS NULL AND
(
`inradar_ad_company`.`corporate_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad_person`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_category`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_subcategory`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad`.`description` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`first_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`last_name` LIKE REPLACE('%$$**$$%', '$$**$$', q)
)
)
) AND
`basicuser`.`subgroup_id` = @subgroup_id AND
dest.longitude BETWEEN lon1 AND lon2 AND dest.latitude BETWEEN lat1 AND lat2
HAVING distance < max_dist
) UNION (
SELECT 3 as `temp`, `inradar_ad`.*, 3956 * 2 * ASIN(SQRT(POWER(SIN((orig.latitude - dest.latitude) * pi()/180 / 2), 2) + COS(orig.latitude * pi()/180) * COS(dest.latitude * pi()/180) * POWER(SIN((orig.longitude - dest.longitude) * pi()/180 / 2), 2))) as distance
FROM
location AS dest
LEFT OUTER JOIN `inradar_ad` ON (`inradar_ad`.location_id = dest.id)
LEFT OUTER JOIN `inradar_ad_company` ON (`inradar_ad`.`id` = `inradar_ad_company`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_ad_person` ON (`inradar_ad`.`id` = `inradar_ad_person`.`inradarad_ptr_id`)
LEFT OUTER JOIN `inradar_category` ON (`inradar_ad`.`category_id` = `inradar_category`.`id`)
LEFT OUTER JOIN `inradar_subcategory` ON (`inradar_ad`.`subcategory_id` = `inradar_subcategory`.`id`)
LEFT OUTER JOIN `basicuser` ON (`inradar_ad`.`owner_id` = `basicuser`.`id`)
LEFT OUTER JOIN `auth_user` ON (`basicuser`.`user_id` = `auth_user`.`id`)
LEFT OUTER JOIN `inradar_ad_multiple` ON (`inradar_ad`.`multiple_advertiser_id` = `inradar_ad_multiple`.`id`),
location AS orig
WHERE orig.id = @location_id AND
(
(
`inradar_ad_multiple`.`id` IS NULL AND
(
`inradar_ad_company`.`corporate_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad_person`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_category`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_subcategory`.`name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`inradar_ad`.`description` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`first_name` LIKE REPLACE('%$$**$$%', '$$**$$', q) OR
`auth_user`.`last_name` LIKE REPLACE('%$$**$$%', '$$**$$', q)
)
)
) AND
`basicuser`.`group_id` = @group_id AND
dest.longitude BETWEEN lon1 AND lon2 AND dest.latitude BETWEEN lat1 AND lat2
HAVING distance < max_dist
)
ORDER by `temp` ASC, distance ASC;
END
但是这会返回重复的条目，如下所示：
# temp, id, seller_id, owner_id, description, category_id, subcategory_id, video_url, logo, location_id, business_hours, subscription_plan_id, tags, advertiser_occupation, advertiser_group_message, email, email_contact_form, website, e_commerce, phone, phone2, blap_phone, delivery, comment_votes, comment_quantity, multiple_advertiser_id, user_type, additional_info, advertiser_available, used_free_coupom, distance
1 37294 40 35 2 37667 (62) 3523-9609 0 0 company 0 0 105.60177674937776
1 37256 36 35 1 37557 (19)4141-5857 0 0 0 company 0 0 233.5020148948106
1 37254 40 35 1 37555 (16) 3624-8409 0 0 company 0 0 297.9775326093067
1 37264 40 35 1 37579 (67) 3251-1186 0 0 company 0 0 829.305941965672
2 37294 40 35 2 37667 (62) 3523-9609 0 0 company 0 0 105.60177674937776
2 37255 52 35 1 37556 (11) 5669-0169 0 0 company 0 0 218.0241298958371
2 37256 36 35 1 37557 (19)4141-5857 0 0 0 company 0 0 233.5020148948106
2 37254 40 35 1 37555 (16) 3624-8409 0 0 company 0 0 297.9775326093067
2 37264 40 35 1 37579 (67) 3251-1186 0 0 company 0 0 829.305941965672
3 37294 40 35 2 37667 (62) 3523-9609 0 0 company 0 0 105.60177674937776
3 37255 52 35 1 37556 (11) 5669-0169 0 0 company 0 0 218.0241298958371
3 37256 36 35 1 37557 (19)4141-5857 0 0 0 company 0 0 233.5020148948106
3 37254 40 35 1 37555 (16) 3624-8409 0 0 company 0 0 297.9775326093067
3 37264 40 35 1 37579 (67) 3251-1186
0 0 company 0 0 829.305941965672
我做错了什么？
非常感谢。
答案 0 :(得分：1)
你可以摆脱UNION并在一个SELECT中完成整个事情。
CASE声明选择您想要的所有内容，并在SELECT子句中设置假var。
SELECT CASE
WHEN `basicuser`.`tertiarygroup_id` = @tertiarygroup_id THEN 1
WHEN `basicuser`.`subgroup_id` = @subgroup_id THEN 2
WHEN `basicuser`.`group_id` = @group_id THEN 3
END as temp, ...
...
WHERE (
`basicuser`.`tertiarygroup_id` = @tertiarygroup_id OR
`basicuser`.`subgroup_id` = @subgroup_id OR
`basicuser`.`group_id` = @group_id
) AND ...
ORDER BY布尔值如果您的三级/二级/组具有树状结构，则可以利用ORDER BY子句中的布尔顺序
ORDER BY cond1 DESC, cond2 DESC, cond3 DESC, distance ASC