Question

我有一个这样的字符串（来自表单提交）：

"apple, banana\r\ncherries\r\n\r\ngrapes, blue berries \r\n\r\n \r\norange"

如何检测值并为每行包含文本的行创建数组？像这样：

[
  ["apple", "banana"],
  ["cherries"],
  ["grapes", "blue berries"],
  ["orange"]
]

Answer 1

require "csv"

str = "apple, banana\r\ncherries\r\n\r\ngrapes, blue berries \r\n\r\n \r\norange"

rows = CSV.parse(str, skip_blanks: true)
rows = rows.map{|row| row.map(&:strip)} # remove leading and trailing whitespace
rows.delete([""]) 

p rows # => [["apple", "banana"], ["cherries"], ["grapes", "blue berries"], ["orange"]]

Answer 2

s = "apple, banana\r\ncherries\r\n\r\ngrapes, blue berries \r\n\r\n \r\norange"
s.each_line.reject { |l| l =~ /^\s+$/ }.map { |l| l.strip.split(', ') }

肯定会有更短的内容

Answer 3

更多相同：

s.each_line.map { |l| l.strip.split(', ') }.reject(&:empty?)

Ruby很有趣！

Answer 4

你可以试试这个：

a = "apple, banana\r\ncherries\r\n\r\ngrapes, blue berries \r\n\r\n \r\norange"
a.gsub("\r", "").each_line.map{|d| d.strip.split(",")}.reject(&:empty?)

......你绝对可以重构这个。

Answer 5

试试这个？

s = "apple, banana\r\ncherries\r\n\r\ngrapes, blue berries \r\n\r\n \r\norange"

result = s.split(/[\r\n]+/).map do |match|
  next unless match =~ /\w/
  match.strip.split(/,\s?/)
end

result.compact # => [["apple", "banana"], ["cherries"], ["grapes", "blue berries"], ["orange"]]

如果简洁更好：

s.split(/[\r\n]+/).map { |m| next unless m =~ /\w/; m.strip.split(/,\s?/) }.compact

具有逗号分隔值和换行符的字符串：拆分值并为每个换行创建数组

5 个答案: