如何在SQL Server 2012中为这样的表拆分字符串:
| ID | Data |
+-----+----------+
| 1 | abc,def |
| 2 | def,abc |
| 3 | def,ghi |
进入这个:
| ID | Data1 | Data2| Data3 |
+-----+-------+------+-------+
| 1 | abc | def | null |
| 2 | abc | def | null |
| 3 | null | def | ghi |
我的目标是获得所有abc的帮助def' s ghi已成为他们自己的专栏。
答案 0 :(得分:1)
使用#Temp表存储已解析的结果。也许你可以迁移到cte
Declare @YourTable table (ID int,Data varchar(max))
Insert Into @YourTable values
(1,'abc,def'),
(2,'def,abc'),
(3,'def,ghi')
Select A.ID
,B.*
,ColName = 'Data'+cast(DENSE_RANK() over (Order By RetVal) as varchar(25))
Into #Temp
From @YourTable A
Cross Apply (
Select RetSeq = Row_Number() over (Order By (Select null))
,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
From (Select x = Cast('<x>'+ Replace(A.Data,',','</x><x>')+'</x>' as xml).query('.')) as A
Cross Apply x.nodes('x') AS B(i)
) B
Declare @SQL varchar(max)
Select @SQL = Stuff((Select Distinct ',' + QuoteName(ColName) From #Temp For XML Path('')),1,1,'')
Select @SQL = 'Select ID,' + @SQL + '
From (Select ID,ColName,RetVal From #Temp) A
Pivot (max(RetVal) For ColName in (' + @SQL + ') ) p'
Exec(@SQL);
返回
ID Data1 Data2 Data3
1 abc def NULL
2 abc def NULL
3 NULL def ghi