Question

好的，这个问题涉及一个复杂的存储过程的一部分，它将新实体插入到几个表中。

我目前遇到困难的部分需要这样工作：

插入具有原始名称的实体
检查新实体的名称是否包含表A“字符”
如果是，则用表A中的“替换字符”替换该字符

例如：#www.test＆amp; aol.com - ＆gt; ＃wwwtest＆amp; aol.com，＃www.test＆amp; aolcom

这是一个艰难的开始，我知道部分内容不起作用，但我认为这是一个不错的起点：

declare @test varchar(50)
set @test = '#www.test&aol.com'
declare @len int, @ctr int
set @len = LEN(@test)
set @ctr = 1

declare @newName varchar(50)
declare @matchedChar table(match varchar(10),replaceChar varchar(10),processed int         default(0))
declare @alternateEntities table(name varchar(50))
declare @repChar varchar(10)
declare @selectedChar varchar(1)

while @ctr<=@len
begin
--Insert matching characters and replacement characters into table variable, 
--this is necessary for the # character, which has multiple replacement characters
insert into @matchedChar (match,replaceChar) select Character,ReplacementCharacter from     tblTransliterations where Character = SUBSTRING(@test,@ctr,1)

--loop 
while (select COUNT(*) from @matchedChar where processed = 0)>0
begin
    --get the top character from table variable
    set @selectedChar = (select top 1 match from @matchedChar where processed = 0)
    --get replacement character
    set @repChar = (select top 1 replaceChar from @matchedChar where processed = 0)
    --replace character in name string
    --set @newName = (select Replace(@test,@selectedChar,@repChar))     
    set @newName = (select STUFF(@test,CHARINDEX(@selectedChar,@test),1,@repChar))
    --update table variable to move onto next character
    update @matchedChar set processed = 1 where @repChar = replaceChar
    --add name with replaced character to alternate entities table
    insert into @alternateEntities (name) values (@newName)     
end
set @ctr = @ctr+1
set @len = LEN(@test)
end

select * from @alternateEntities

Answer 1

使用基于集合的方法，而不是循环。

创建临时表并填充NVARCHAR（100）类型的“单词”列，调用临时表Invalid_Words
为每个令牌在Invalid_Words上创建一个列，并使col type = bit
如果单词通过一系列更新语句包含令牌，则更新临时表位列

您现在已经定义了每个单词匹配的标记。

下一部分是替换。

如何检查字符串中的字符并在插入之前替换该字符

1 个答案: