Question

我当前正在尝试在消息的最后一个字符之后插入字符串。因此，最初的消息是：

谢谢。您的订单已收到。

现在，我想在d和.之间插入另一个字符串。这是我尝试过的方法，但是没有用：

$received_text = substr_replace( $received_text, ', but must be payed', substr( $received_text, - 1 ), 0 );

它正在插入我的消息的开头。任何帮助都很好！

Answer 1

<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.6.9/angular.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.9/angular-sanitize.js"></script>


<div ng-app="myApp" ng-controller="myCtrl">
<pre>
 <div ng-bind-html="myText"></div>
</pre>
</div>

Answer 2

您可以使用TelephonyManager tm = (TelephonyManager)context.getSystemService(Service.TELEPHONY_SERVICE); tm.listen(listener, PhoneStateListener.LISTEN_CALL_STATE); PhoneStateListener listener = new PhoneStateListener() { @Override public void onCallStateChanged(int state, String incomingNumber) { // TODO Auto-generated method stub super.onCallStateChanged(state, incomingNumber); switch(state) { case TelephonyManager.CALL_STATE_IDLE: break; case TelephonyManager.CALL_STATE_OFFHOOK: if(incomingNumber==null) { //outgoing call } else { //incoming call } break; case TelephonyManager.CALL_STATE_RINGING: if(incomingNumber==null) { //outgoing call } else { //incoming call } break; } } };将字符串拆分为所需的部分，并在它们之间添加新的部分

substr()

PHP documentation for substr

Answer 3

基于substr_replace() Manual

开始

如果start为非负数，则替换将从字符串的第start个偏移量开始。

如果start为负，则替换将从字符串末尾的第一个字符开始。

因此，基本上，您必须提供一个数值，以便替换从该特定位置本身开始。

执行以下操作：-

<?php
$received_text ='Thank you. Your order has been received.';
echo $received_text = substr_replace( $received_text, ', but must be payed', (strlen($received_text) - 1), 0 );

输出：-{https://3v4l.org/ihLOk

Answer 4

您可以使用此代码段在任何字符串之后插入字符串。

$received_text = "Thank you. Your order has been received.";
$search_string = "received"; //string AFTER which you want to insert another
$insert_string = " now"; //string to be inserted
$position = strpos(strtolower($received_text), strtolower($search_string))+strlen($search_string); //strpos is case sensitive

$received_text = substr_replace($received_text, $insert_string, $position,0);

echo $received_text;

希望它会有所帮助：）

PHP：在最后一个字符之前插入字符串

4 个答案: