EmbeddedModelField在自定义用户模型中

时间:2014-03-29 10:49:27

标签: python django python-2.7 django-nonrel django-mongodb-engine

我使用django-mongodb-engine制作网站。

我有一个自定义用户模型,如下所示:

class User(AbstractUser):
    trigrama = models.CharField(max_length=3, unique=True)
    external_email = models.EmailField(unique=True)
    phone_number = models.CharField(max_length=20, unique=True)

    AbstractUser._meta.get_field_by_name('email')[0]._unique=True

    USERNAME_FIELD = 'email'
    REQUIRED_FIELDS = [
        'first_name', 'last_name', 'trigrama',
        'external_email', 'phone_number', 'username'
    ]

它工作正常,但后来我尝试将嵌入文档添加到用户模型中:

    permissions = EmbeddedModelField('Permission')

Permission是一个如下所示的类:

class Permission(models.Model):
    computers = ListField(EmbeddedModelField('Computer'))
    projects = ListField(EmbeddedModelField('Project'))
    scripts = ListField(EmbeddedModelField('Script'))

现在,当我尝试使用User.objects.create()在shell中创建用户时,我收到以下错误:

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 149, in create
    return self.get_query_set().create(**kwargs)
  File "C:\Python27\lib\site-packages\django\db\models\query.py", line 416, in create
    obj.save(force_insert=True, using=self.db)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 548, in save
    force_update=force_update, update_fields=update_fields)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 668, in save_base
    result = manager._insert([self], fields=fields, return_id=update_pk, using=using, raw=raw)
  File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 215, in _insert
    return insert_query(self.model, objs, fields, **kwargs)
  File "C:\Python27\lib\site-packages\django\db\models\query.py", line 1675, in insert_query
    return query.get_compiler(using=using).execute_sql(return_id)
  File "C:\Python27\lib\site-packages\djangotoolbox\db\basecompiler.py", line 583, in execute_sql
    "field) to None!" % field.name)
IntegrityError: You can't set permissions (a non-nullable field) to None!

我尝试使用以下内容将默认值设置为Permission()

permissions = EmbeddedModelField('Permission', default=Permission())

然后我收到以下错误:

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 149, in create
    return self.get_query_set().create(**kwargs)
  File "C:\Python27\lib\site-packages\django\db\models\query.py", line 416, in create
    obj.save(force_insert=True, using=self.db)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 548, in save
    force_update=force_update, update_fields=update_fields)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 668, in save_base
    result = manager._insert([self], fields=fields, return_id=update_pk, using=using, raw=raw)
  File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 215, in _insert
    return insert_query(self.model, objs, fields, **kwargs)
  File "C:\Python27\lib\site-packages\django\db\models\query.py", line 1675, in insert_query
    return query.get_compiler(using=using).execute_sql(return_id)
  File "C:\Python27\lib\site-packages\djangotoolbox\db\basecompiler.py", line 579, in execute_sql
    connection=self.connection
  File "C:\Python27\lib\site-packages\djangotoolbox\fields.py", line 364, in get_db_prep_save
    (embedded_model, type(embedded_instance)))
TypeError: Expected instance of type <class 'users.models.Permission'>, not <type 'unicode'>.

那么我应该如何将嵌入式文档添加到自定义用户模型中呢?

P.S。 如果我在shell中键入Permission()它实例化就好了,返回Permission object而不是unicode。

1 个答案:

答案 0 :(得分:3)

If you read the docs关于为字段设置默认值的方式,您会发现它希望收到一个值...或a callable object。你不能只是在那里创建实例,它不会像那样工作(强调我的):

  

默认值不能是可变对象(模型实例,列表,集,   等),作为对该对象的同一实例的引用   用作所有新模型实例中的默认值。

当你自己调用它时(即Permission())你得到的是一个实例,它反过来又返回一个unicode(它调用__unicode__函数)。

换句话说,只需删除尾随()

permissions = EmbeddedModelField('Permission', default=Permission)

现在,说实话,这可能会有问题,因为它实际上并没有保存新的权限对象,整个事情可能会变得混乱(这是权限和所有,你想要的要格外小心)。因此,创建一个包装操作的函数可能会更好,并使用它来代替:

def get_initial_perms():
    p = Permission()
    p.save()
    return p

# later:
permissions = EmbeddedModelField('Permission', default=get_initial_perms)

类似的解决方案是覆盖save()方法并在调用实际save部分之前为对象提供权限。