Question

如何在Android请求中添加自定义[回调]字符串？

下面是我在android中调用soap webservice的代码，并得到一个json响应。如何在android中传递调用back=?callback=jQuery15？

有关相同内容的任何想法如何在网址中包含callback-jquery15个参数？

private static String SOAP_ACTION1 = "http://www.example.com/NewsServices/AuthenticateApplication";
    private static String NAMESPACE = "http://www.example.com/NewsServices/";
    private static String METHOD_NAME1 = "AuthenticateApplication";
    private static String URL = "http://www.example.com/services/webServices/MobileServices/exampleMobilejson.asmx";




SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME1);
        request.addProperty("xyz", "xyzaa");
        request.addProperty("abc", "abcxx");
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);
        envelope.setOutputSoapObject(request);
        envelope.dotNet = true;
        try {
            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
            androidHttpTransport.call(SOAP_ACTION1, envelope);
            SoapObject result = (SoapObject) envelope.bodyIn;
            Toast.makeText(getApplicationContext(), result.toString(),
                    Toast.LENGTH_LONG).show();
            txtCel.setText(result.getProperty(0).toString());

但我的问题是我的webservice接受参数，回调如何使用ex：

http://www.example.com/services/webServices/MobileServices/exampleMobileJson.asmx/AuthenticateApplication?callback=jQuery15&xyz=xyzaa&abc=abcxx

Answer 1

回调通常用于JSONP。当您在浏览器中对位于其他域中的Web服务器执行AJAX请求时。由于“同源政策”，它将被阻止。使用JSONP，您可以避免添加回调参数。此参数是您网页中定义的函数调用。

关于添加额外参数：

request.addProperty("callback", "jQuery15");

就像你已经用于'xyz'和'abc'。

如何在android请求中添加自定义[回调]字符串？

1 个答案: