下面是我在android中调用soap webservice的代码并获取json响应
如何在android中传递回调=?callback = jQuery15任何指导???????
任何关于相同的想法如何在url中包含?callback-jquery15参数?
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME1);
request.addProperty("xyz", "xyzaa");
request.addProperty("abc", "abcxx");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
try {
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION1, envelope);
SoapObject result = (SoapObject) envelope.bodyIn;
Toast.makeText(getApplicationContext(), result.toString(),
Toast.LENGTH_LONG).show();
txtCel.setText(result.getProperty(0).toString());
但我的问题是我的webservice接受参数,回调如何使用ex: