我正在尝试绘制一条链接边界框中心点的线,当中心逐帧移动时,这些点存储在矢量中。
现在我正在尝试使用CvLine将这些点与一条线连接在一起。我关注This Opencv Documentation。但是CvLine函数很合适我给它的参数。
以下是代码:
vector<Point> Rightarm(20);
vector<Point> Leftarm(20);
vector<Point>::const_iterator RightIter;
vector<Point>::const_iterator LeftIter;
Point center = Point(oko[0].x + (oko[0].width/2), oko[0].y + (oko[0].height/2));
cout<<"Center Point of Box: 0 is: " <<center<<endl;
double area = (oko[0].width * oko[0].height);
cout<<"The Area of Box: 0 is: " <<area<<endl;
Point center1 = Point(oko[1].x + (oko[1].width/2), oko[1].y + (oko[1].height/2));
cout<<"Center Point of Box: 1 is: " <<center1<<endl;
double area1 = (oko[1].width * oko[1].height);
cout<<"The Area of Box: 1 is: " <<area1<<endl;
Rightarm.push_back(center);
Leftarm.push_back(center1);
if(oko[0].x > oko[1].x)
{
}
else
{
}
for(RightIter = Rightarm.begin(); RightIter != Rightarm.end(); ++RightIter)
{
circle(drawing, *RightIter, 3, Scalar(0,0,255), CV_FILLED);
}
if(Rightarm.size() == 20)
{
Rightarm.clear();
}
for(LeftIter = Leftarm.begin(); LeftIter != Leftarm.end(); ++LeftIter)
{
circle(drawing, *LeftIter, 3, Scalar(0,255,0), CV_FILLED);
}
if(Rightarm.size() == 20)
{
Leftarm.clear();
}
cvLine(drawing, center.x, center.y, Scalar(255,255,255),1 ,8 ,CV_AA);
imshow(window_Input, frame);
imshow(window_Output, drawing);
任何人都可以看到我出错的地方......?
答案 0 :(得分:2)
你给错误的参数和一个额外的参数给行功能。您指向的文档用于Python接口,也是使用cv
的旧文档。假设您有最新版本的OpenCV,那么在Python中使用新的C ++接口或cv2
接口会更好。
你必须使用像
这样的行功能cvLine(
img, // image to draw on
center, // starting end point of line segment of type cv::Point
center1, // other end of line segment
Scalar(0, 255, 0), //green colour
1 // thickness of line
CV_AA // anti aliased line type
);
文档是here
答案 1 :(得分:2)
也许是这样的:
struct centerpoint {
int x;
int y;
} center1,center2;
(...) //Define values for centers.
cvLine( drawing,
cvPoint(center1.x, center1.y),
cvPoint(center2.x, center2.y),
Scalar(255,255,255), 1, 8 , CV_AA);
不要忘记投票给你喜欢的所有答案,并接受有效的答案。
答案 2 :(得分:0)
cvLine在两点之间画线,你应该给它两个cv :: Point而不是center.x nad center.y