Question

在此程序中，球体将围绕由立方体包围的3d空间移动。球体将移动直到它们撞到墙壁或另一个球体。如果他们撞墙，他们就会被摧毁。如果它们击中另一个球体，则较小的球体将被摧毁。

球体以x，y，z坐标给出，半径为r，dx，dy，dz为移动。

程序的一般要点是遍历球体对象列表，并使用距离公式来查看它是否小于检测碰撞的半径。

无论如何，我在运行时期间继续在Visual Studio中遇到错误“列表迭代器不可递增。但是，程序在Linux g ++编译器上运行时没有错误。看起来在尝试检测球体碰撞时会出现问题当该部分被注释掉时，该程序仍然有效。

// This is where our spheres are moved
s = sphereList.begin();                     //set iterator to beginning of list

while(s != sphereList.end())                //This loop moves the spheres
{
    bool firstRun = true;
    double x,y,z,r,xj,yj,zj,dist,radii,area1,area2;         //Temp x,y,z,r

    Point newCenter;        //Temp Center for movement calculatio n

    x = s->getX()+s->getdx();
    y = s->getY()+s->getdy();
    z = s->getZ()+s->getdz();
    r = s->getRadius();

    newCenter.setX(x);
    newCenter.setY(y);
    newCenter.setZ(z);

    s->setCenter(newCenter);    //replaces existing sphere with new coordinates

    //check if the sphere has reached the edge of the cube at 0 or 1000 units 
    if(x+r >= MAX_CUBE || x-r <= MIN_CUBE || y+r >= MAX_CUBE || y-r <= MIN_CUBE || z+r >= MAX_CUBE || z-r <= MIN_CUBE)
    {
        cout << "  " << s->getElement() << "         " << (int)time << "         " << "Boundary" << endl;
        s = sphereList.erase(s);
        time = 1 * TIME_VALUE;
    }

    std::list<Sphere>::iterator j = sphereList.begin();         //second iterator
        j++;
    while(j != sphereList.end())
    {
        xj = j->getX();
        yj = j->getY();
        zj = j->getZ();

        dist = sqrt(((x-xj)*(x-xj))+((y-yj)*(y-yj))+((z-zj)*(z-zj)));

        //cout << dist << endl;
        radii = s->getRadius() + j->getRadius();

        if(dist < radii)
        {

            if(s->getRadius() < j->getRadius())
            {
                cout << "  " << s->getElement() << "         " << (int)time << "         " << "Collision" << endl;
                s = sphereList.erase(s);
                time = 1 * TIME_VALUE;
                break;
            }
            else
            {
                cout << "  " << j->getElement() << "         " << (int)time << "         " << "Collision" << endl;
                j = sphereList.erase(j);
                time = 1 * TIME_VALUE;
                break;
            }
        }
    j++;
    }
    time++;


}

Answer 1

在下面的循环中，您要多次递增i，您确定要有这么多元素吗？

while(i != doubleList.end())
{

Answer 2

如果s和j位于列表中的相同位置，则会删除j，这会使s无效。

您不必每次都从头开始j，因为您已经将它与s前面的每个元素进行了比较。

我想替换

j = sphereList.begin();

带

j = s;

应该足够了。

程序检测碰撞球体时出错

2 个答案: