Question

如何使用jquery迭代这个json消息的嵌套数组（即“orders”）？

[{"Type":"X","Symbol":"AAP","BidPrice":17.0,
"OfferPrice":0.0,"BidQty":9,"OfferQty":0,"LastTradePrice":17.0,
"orders":[{"BidQuantity":"12","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
"BidQuantity":"2","BidPrice":"16.0","OfferQuantity":"","OfferPrice":""}]}

我尝试过以下方式但不起作用

$.each(data, function(i, item) {
   $('#last').text(data[i].LastTradePrice);

   var ords = item.orders;  
   $.each(ords, function(x,ork) {
    alert(ork[x].BidPrice);
   });                                      
});

我在firefox控制台中收到以下错误

ork [x]未定义

Answer 1

您的json在"orders:[无效，应该是"orders":[，您也忘了将orders数组中的每个对象都包含}。在任何情况下，下面都会更正JSON。

在任何情况下，您都不需要使用jquery来做这样的事情：

for(var i = 0; i < inputs.length; i++) {
    alert(inputs[i].BidPrice);
}

Orders是类型数组，我严重怀疑你需要使用jQuery，但无论如何： http://jsfiddle.net/kyWGT/14/

var data =     
   [{"Type":"X","Symbol":"AAP","BidPrice":17.0,
   "OfferPrice":0.0,"BidQty":9,"OfferQty":0,"LastTradePrice":17.0,
   "orders":[{"BidQuantity":"12","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
             {"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
             {"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""}, {"BidQuantity":"2","BidPrice":"16.0","OfferQuantity":"","OfferPrice":""}]
   }];

$.each(data, function(i, item) {
   $('#last').text(data[i].LastTradePrice);

   var ords = item.orders;  
    $.each(ords, function(i, ork) {
        alert(ork.BidPrice);
    });
});

Answer 2

$.each使用索引和项调用回调。该项不需要具有名为该索引的属性，该数据具有。

$.each(data, function(i, item) {
    item === data[i];
})

因此，请勿在代码中使用data[i]，item，并且不要使用ords[x]或ork[x]，而应使用ork。另外：如果您不需要，请不要使用迭代器功能！ Javascript具有内置循环语法： - ）

for (var i=0; i<data.length; i++) {
    $('#last').text(data[i].LastTradePrice);
    var ords = data[i].orders;  
    for (var j=0; j<ords.length; j++)
        alert(ords[j].BidPrice);
}

......这要快得多。此外，如果您知道结果数据只有一个项目，则可以省略外部循环并使用data[0]。

Answer 3

你的JSON还有其他错误，我认为正确的JSON就是：

[{"Type":"X","Symbol":"AAP","BidPrice":17.0,
"OfferPrice":0.0,"BidQty":9,"OfferQty":0,"LastTradePrice":17.0,
"orders":[{"BidQuantity":"12","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"2","BidPrice":"16.0","OfferQuantity":"","OfferPrice":""}]}]

假设这是对的，你的jQuery几乎就在那里。在第二个回调中，'ork'是订单对象，您不需要用'x'对其进行索引。这应该有效：

$.each(ords, function(x,ork) {
    alert(ork.BidPrice);
});

如果您复制/粘贴此代码，它应该有用，它适用于我：

var data = [{"Type":"X","Symbol":"AAP","BidPrice":17.0,
"OfferPrice":0.0,"BidQty":9,"OfferQty":0,"LastTradePrice":17.0,
"orders":[{"BidQuantity":"12","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
{"BidQuantity":"2","BidPrice":"16.0","OfferQuantity":"","OfferPrice":""}]}]

$.each(data, function(i, item) {
    var ords = item.orders;
    $.each(ords, function(i, ork) {
        alert(ork.BidPrice);
    });
});

Answer 4

假设这是你的Json

   var sbk = 
     [{"Type":"X","Symbol":"AAP","BidPrice":17.0,
      "OfferPrice":0.0,"BidQty":9,"OfferQty":0,"LastTradePrice":17.0,            
      "orders":[{"BidQuantity":"12","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
      {"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
      {"BidQuantity":"5","BidPrice":"17.0","OfferQuantity":"","OfferPrice":""},
      {"BidQuantity":"2","BidPrice":"16.0","OfferQuantity":"","OfferPrice":""}] }];

这是你的剧本：

  $.each(sbk, function(i, item) {
      var ords = item.orders;  
      $.each(ords, function(i, ork) {
                 console.log(ork.BidPrice);
                 alert(ork.BidPrice);
      });

点击此处： http://jsfiddle.net/JH6A7/10/

Answer 5

将我的代码更改为以下方式，它对我非常有用。

$.each(data, function(i, item) {
  alert(data[i].Symbol); /* retrieve values from first json array */
  if(data[i].orders != null){   
     for(var j=0; j<data[i].orders.length; j++){
        alert(item.orders[j].BidPrice);/* retrieve json values from nested array */
     }
  }
}

对不起因答案延迟回复，我正忙着工作一段时间...... 感谢所有试图提供帮助的人。

如何使用jquery迭代json消息的嵌套数组？

5 个答案: