解决了它
我编写了一个程序，在等号后加载字符串，并计算完成它的次数。在计数之后，我告诉它告诉我int的大小。我正在寻找的值是3，它告诉我，3。然后我将它改为String，值保持为3。然后，我把它放入一个4d数组，它告诉我值是2.发生了什么？
守则：
int times=0;
else if (list.equals("Weapon")) {//If the word weapon is before the =
weapon = value; //take the string after the = and put it into String weapon
troopStats[times][1][weaponTimes][0] = weapon;
weaponTimes++;
System.out.println(weaponTimes+"weapontimes"+times);
}
weaponTimesStr = Integer.toString(weaponTimes);
System.out.println(weaponTimesStr+"string");
troopStats[times][1][0][1] = weaponTimesStr;
System.out.println(troopStats[times][1][0][1]+"InArray");
times++
//loops
输出：
3weapontimes //Counted the equals sign 3 times, Note that this is from the part of the
omitted code
3string // Changed the integer to a string and got 3
2InArray // Put it into an array, and got 2 back
发生了什么事？
（我知道我可以只为该值添加1，但我希望稍后将此代码用于未知数量的事情）
为了提供帮助，我发布了整个代码：
public class TroopLoader {
static String[][][][] troopStats;
static int times = 0;
static int weaponTimes = 0;
static int armorTimes = 0;
static int animalTimes = 0;
static String weaponTimesStr;
static String armorTimesStr;
static String animalTimesStr;
static String troop;
static String weapon;
static String armor;
static String animal;
static String speed;
static int total = 0;
/*
* [][][]
*
* [total number of troops (total)]
*
* [stats] 0= name 1= weapon 2= armor 3= animal 4= speed
*
* [different things within stat]
*/
public void readTroop() {
File file = new File("resources/objects/troops.txt");
BufferedReader reader = null;
try {
reader = new BufferedReader(new FileReader(file));
String text = null;
// repeat until all lines is read
while ((text = reader.readLine()) != null) {
StringTokenizer troops = new StringTokenizer(text, "=");
if (troops.countTokens() == 2) {
String list = troops.nextToken();
if (list.equals("Troop")) {
total++;
}
else {
}
} else {
}
}
troopStats = new String[total][5][10][2];
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally {
try {
if (reader != null) {
reader.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
File file2 = new File("resources/objects/troops.txt");
BufferedReader reader2 = null;
try {
reader2 = new BufferedReader(new FileReader(file2));
String text = null;
// repeat until all lines is read
while ((text = reader2.readLine()) != null) {
StringTokenizer troops = new StringTokenizer(text, "=");
if (troops.countTokens() == 2) {
String list = troops.nextToken();
String value = troops.nextToken();
if (list.equals("Troop")) {
troop = value;
troopStats[times][0][0][0] = troop;
}
else if (list.equals("Weapon")) {
weapon = value;
troopStats[times][1][weaponTimes][0] = weapon;
weaponTimes++;
System.out.println(weaponTimes+"weapontimes"+times);
}
else if (list.equals("Armor")) {
armor = value;
troopStats[times][2][armorTimes][0] = armor;
armorTimes++;
}
else if (list.equals("Animal")) {
animal = value;
troopStats[times][3][animalTimes][0] = animal;
animalTimes++;
}
else if (list.equals("Speed")) {
speed = value;
troopStats[times][4][0][0] = speed;
}
else if (list.equals("Done")) {
weaponTimesStr = Integer.toString(weaponTimes);
System.out.println(weaponTimesStr+"string");
armorTimesStr = Integer.toString(armorTimes);
animalTimesStr = Integer.toString(animalTimes);
troopStats[times][1][0][1] = weaponTimesStr;
troopStats[times][1][0][1] = armorTimesStr;
troopStats[times][1][0][1] = animalTimesStr;
System.out.println(troopStats[times][1][0][1]+"InArray"+times);
times++;
troop = "";
weapon = "";
armor = "";
animal = "";
speed = "";
weaponTimes = 0;
armorTimes = 0;
animalTimes = 0;
}
else {
}
} else {
}
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally {
try {
if (reader2 != null) {
reader2.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
在代码的早期部分，我让程序使用weaponTimes变量在数组中的位置存储一个值，而不是存储weaponTimes变量。我的错，抱歉浪费你的时间。
答案 0 :(得分：3)
我用你发布的内容写了一个SSCCE，并打印出你所期望的内容：
public static void main(String[] args) {
String[][][][] troopStats = new String[4][4][4][4];
int times = 2;
int weaponTimes = 3;
String weaponTimesStr = Integer.toString(weaponTimes);
System.out.println(weaponTimesStr + "string"); //prints 3string
troopStats[times][1][0][1] = weaponTimesStr;
System.out.println(troopStats[times][1][0][1] + "InArray"); //prints 3InArray
}
所以这个问题最有可能发生在其他地方。
答案 1 :(得分：3)
以下内容：
public class Foo {
public static void main(String[] args) {
String[][][][] troopStats = new String[2][2][2][2];
String weaponTimesStr = Integer.toString(3);
System.out.println(weaponTimesStr+"string");
troopStats[0][1][0][1] = weaponTimesStr;
// You said in a comment that 'times' is equal to 0 in this case so have subbed that in
System.out.println(troopStats[0][1][0][1]+"InArray");
}
}
给我预期的输出：
3string
3InArray
答案 2 :(得分：0)
抱歉，我浪费了你的时间，我的错误是因为我使用weaponTimes的值在数组中存储值，而不是在数组中存储weaponTimes。
troopStats[times][1][weaponTimes][0] = weapon;
这是错误的。