在C#中的pictureBox中显示一个字节数组

时间:2012-04-02 18:27:07

标签: c# bitmap picturebox

我读了很多问题和答案,大多数建议:

byte[] byteArray; //(contains image data)
MemoryStream stream = new MemoryStream(byteArray);
Bitmap image = new Bitmap(stream);
pictureBox.Image = image;

或更直接:

pictureBox.Image = Image.FromStream(stream);

我总是得到:“System.Drawing.dll中发生了'System.ArgumentException'类型的未处理异常

附加信息:参数无效。“

关于stream参数。

即使在以下情况下:

byte[] byteArray = new byte[1];
byteArray[0] = 255;

我无法弄清楚原因。

编辑:

我从这样的文件中获取数据:

//byteArray is defined as List<byte> byteArray = new List<byte>();
TextReader tr = new StreamReader(file);
string File = tr.ReadToEnd();
string[] bits = File.Split('\t');
List<string> image = new List<string>(bits);
height = int.Parse(bits[0]);
width  = int.Parse(bits[1]);
image.RemoveRange(0, 2);
image.RemoveAt(image.Count - 1);
foreach (string s in image)
{
  byteArray.Add(byte.Parse(s));
}
return byteArray //(i do .ToArray() in the MemoryStream call);

在调试器中,我看到,即byteArray是好的,count = 2244,值到处都是等等。

编辑#2:样本数据文件(第一个字节[0]是高度,第二个字节[1]是宽度,其余是RGB数据)

47 15 12 55 25 52 55 25 52 55 25 52 55 25 52 55
25 52 55 25 52 55 25 52 55 25 52 55 25 52 55 25
52 55 25 52 55 25 52 55 25 52 55 25 52 55 25 52
55 25 52 55 25 52 55 25 52 55 25 52 55 25 52 55
25 52 51 24 82 49 24 82 49 24 92 50 25 12 50 24
92 48 24 92 50 24 82 50 25 02 50 24 92 50 25 02
51 25 12 50 24 92 49 25 02 50 25 02 49 25 12 49
25 02 49 25 02 47 25 12 47 25 22 50 24 82 47 24
82 50 24 72 50 24 82 49 24 82 50 24 72 50 24 82
50 24 72 49 24 82 49 25 22 52 24 92 50 24 82 50
24 72 47 25 00 etc.

编辑#3:解决方案

Bitmap bmp = new Bitmap(width, height, PixelFormat.Format24bppRgb);
BitmapData bmpData = bmp.LockBits(new Rectangle(0, 0, width, height), ImageLockMode.WriteOnly, PixelFormat.Format24bppRgb);
IntPtr ptr = bmpData.Scan0;
Marshal.Copy(byteArray, 0, ptr, height * width * 3);
bmp.UnlockBits(bmpData);
pictureBox.Image = bmp;

需要检查4字节对齐,现在加载功能:

TextReader tr = new StreamReader(file);
string File = tr.ReadToEnd();
string[] bits = File.Split('\t');
List<string> image = new List<string>(bits);
height = int.Parse(bits[0]);
width  = int.Parse(bits[1]);
int falseBits = 0;
int oldWidth = width;
while (width % 4 != 0)
{
    width++;
    falseBits++;
}
int size = height * width * 3;
byte[] byteArray = new byte[size];
Parallel.For(0, size - 1, i => byteArray[i] = 255);
int index  = 0;
int lineIndex = 0;
image.RemoveRange(0, 2);
image.RemoveAt(image.Count - 1);
foreach (string s in image)
{
    byteArray [index]   = byte.Parse(s);
    byteArray [index + 1] = byteArray [index];
    byteArray [index + 2] = byteArray [index];
    index +=3;
    lineIndex++;
    if (lineIndex == oldWidth)
    {
        lineIndex = 0;
        index += 3*falseBits;
    }
}
return byteArray ;

2 个答案:

答案 0 :(得分:2)

每个Image都需要描述字节数组的内容。此描述称为Header。如果您现在想要交换字节,则需要避免更改标题。

http://en.wikipedia.org/wiki/BMP_file_format

这是我使用这样一个ByteArray时的源代码示例

''' <summary>
''' Copies an Bytearray into an image and return it.
''' </summary>
''' <param name="ArrSrc">Source byte array of image which can be anything</param>
''' <param name="ImageSize">the image size of the image</param>
''' <param name="SourceArrayPixelFormat">Pixel format, like 24Bit or 32Bit</param>
''' <returns>System.Drawing.Image</returns>
''' <remarks>copyright, http://software.goldengel.ch, 2012</remarks>
Public Function ArrayToBitmapData(ByVal ArrSrc() As Byte, ByVal ImageSize As System.Drawing.Size, ByVal SourceArrayPixelFormat As System.Drawing.Imaging.PixelFormat) As System.Drawing.Bitmap
    'Kopiert ein ByteArray in ein Bitmap

    Dim m As Integer
    Dim bmTemp As System.Drawing.Bitmap = Nothing
    Dim S As System.Drawing.Size
    Dim MemorySize As Integer
    Dim ScanLine As Integer

    'Bild prüfen
    If ArrSrc Is Nothing Then Return bmTemp

    'Bildgrösse definieren
    'Bei unterschiedlichen Grössen, wird muss die kleinere Grösse verwendet werden
    S = ImageSize


    'Helfer für die Bildverarbeitung erzeugen
    Dim bts As System.Drawing.Imaging.BitmapData

    'Bitmap erzeugen um damit zu arbeiten
    bmTemp = New System.Drawing.Bitmap(S.Width, S.Height, SourceArrayPixelFormat)

    'Farbtiefe berechnen
    '24Bit und 32Bit Bilder werden unterstützt
    'Kann beliebig erweitert werden
    m = BytesInPixelFormat(SourceArrayPixelFormat)



    '*** Hauptroutine - Array --> Bitmap ***

    'Bilddaten in die Picturebox laden
    bts = bmTemp.LockBits(New System.Drawing.Rectangle(0, 0, S.Width, _
        S.Height), System.Drawing.Imaging.ImageLockMode.WriteOnly, SourceArrayPixelFormat)


    'Speicherplatz reservieren
    'MemorySize = S.Height * S.Width * m
    'Nur zur Kontrolle
    ScanLine = GetScanline(S, SourceArrayPixelFormat)

    MemorySize = S.Height * bts.Stride
    If ArrSrc.Length >= MemorySize Then
        'Bilddaten aus dem Array laden
        Global.System.Runtime.InteropServices.Marshal.Copy(ArrSrc, 0, bts.Scan0, MemorySize)
    End If
    bmTemp.UnlockBits(bts)

    'Erzeugtes Bitmap zurückgeben
    Return bmTemp

End Function



convert Bitmap image into byte array

'Neue Funktion 27.2.2008
'Mit korrekter Dimensionierung mittels bts.Stride und Umrechnung auf das Pixelformat
''' <summary>
''' Get an Array of the data of any image. 
''' Bitmap header execluded.
''' </summary>
''' <param name="bmSrc">Source image</param>
''' <param name="NeededDestinationPixelFormat">Pixelformat, like 24Bit or 32Bit</param>
''' <returns>Image content</returns>
''' <remarks>copyright http://software.goldengel.ch, 2012</remarks>
Public Function BitmapDataToArray(ByVal bmSrc As System.Drawing.Bitmap, ByVal NeededDestinationPixelFormat As System.Drawing.Imaging.PixelFormat, ByRef DstStride As Integer) As Byte()
    'Kopiert ein Bild in ein Bytearray

    Dim m As Integer
    Dim A() As Byte = Nothing
    Dim S As System.Drawing.Size
    Dim MemorySize As Integer
    Dim bmTemp As System.Drawing.Bitmap = Nothing

    'Bild prüfen
    If bmSrc Is Nothing Then Return A

    'Bildgrösse definieren
    'Bei unterschiedlichen Grössen, wird muss die kleinere Grösse verwendet werden
    S = bmSrc.Size


    'Helfer für die Bildverarbeitung erzeugen
    Dim bts As System.Drawing.Imaging.BitmapData

    'Farbtiefe berechnen
    '24Bit und 32Bit Bilder werden unterstützt
    'Kann beliebig erweitert werden
    m = BytesInPixelFormat(NeededDestinationPixelFormat)


    '*** Hauptroutine - Bitmap --> Array ***
    'Bilddaten aus der Picturebox laden
    If NeededDestinationPixelFormat <> bmSrc.PixelFormat Then
        'Bitmap erzeugen um damit zu arbeiten
        bmTemp = New System.Drawing.Bitmap(S.Width, S.Height, NeededDestinationPixelFormat)

        Using gr As System.Drawing.Graphics = System.Drawing.Graphics.FromImage(bmTemp)
            gr.DrawImage(bmSrc, 0, 0)
        End Using
        'ImgSrc.Dispose()'Achtung, würde das Original mit zerstören
        bmSrc = bmTemp
    End If

    bts = bmSrc.LockBits(New System.Drawing.Rectangle(0, 0, S.Width, _
        S.Height), System.Drawing.Imaging.ImageLockMode.ReadOnly, NeededDestinationPixelFormat)

    'Speicherplatz reservieren
    MemorySize = S.Height * bts.Stride
    ReDim A(MemorySize - 1) '28.2.2010. wichtige Änderung. 1 Byte zuviel wurde reserviert. Das konnte bei Wiederholung von Graphics.Drawing zu einem Fehler kommen

    'Bitmapdaten in das Array kopieren
    Global.System.Runtime.InteropServices.Marshal.Copy(bts.Scan0, A, 0, A.Length)
    bmSrc.UnlockBits(bts)

    DstStride = bts.Stride

    If bmTemp IsNot Nothing Then bmTemp = Nothing

    Return A

End Function

答案 1 :(得分:1)

根据您帖子顶部的原始建议,我对此工作没有任何问题。

pictureBox.Image = GetImage();

public Image GetImage()
{
    Image image;
    using (FileStream fs = File.OpenRead(@"C:\picture.jpg"))
    {
        long length = fs.Length;

        byte[] bytes = new byte[length];

        for (int pos = 0; pos < length; )
            pos += fs.Read(bytes, pos, (int)length - pos);

        fs.Position = 0;

        using (MemoryStream ms = new MemoryStream(bytes))
            image = Image.FromStream(ms);
    }

    return image;
}

现在,无论这是否安全/正确,我都不知道,但似乎有效。