从android中的活动启动广播接收器

时间:2012-04-02 08:01:12

标签: android broadcastreceiver

我想从一项活动中启动广播接收器。我有一个Second.java文件,它扩展了广播接收器和Main.java文件,我必须从中启动广播接收器。 我也尝试在Main.java中执行如下操作,但不知道如何在清单文件中定义...

Main.java:

public class Main extends Activity {
/** Called when the activity is first created. */
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
String rec_data = "Nothing Received";
private BroadcastReceiver myReceiver = new BroadcastReceiver() {

        public void onReceive(Context context, Intent intent) {
            // TODO Auto-generated method stub
            if( intent.getStringExtra("send_data")!=null)
                    rec_data = intent.getStringExtra("send_data");
            Log.d("Received Msg : ",rec_data);
        }
    }; 
    }
    protected void onResume() {
        IntentFilter intentFilter = new IntentFilter();
        //intentFilter.addDataType(String);
        registerReceiver(myReceiver, intentFilter);
        super.onResume();
    }

  @Override
protected void onPause() {
// TODO Auto-generated method stub
    super.onPause();
    this.unregisterReceiver(this.myReceiver);
}

}

如果我不能像上面那样在一个班级做所有事情,我如何从Main.java调用广播接收器?任何人都可以让我知道我做错了吗?谢谢!

4 个答案:

答案 0 :(得分:28)

使用此原因发送自定义广播:

定义一个动作名称:

public static final String BROADCAST = "PACKAGE_NAME.android.action.broadcast";

AndroidManifest.xml注册接收者:

<receiver android:name=".myReceiver" >  
    <intent-filter >  
        <action android:name="PACKAGE_NAME.android.action.broadcast"/>  
    </intent-filter>  
</receiver> 

Register Reciver:

IntentFilter intentFilter = new IntentFilter(BROADCAST);
registerReceiver( myReceiver , intentFilter);

从您的活动发送广播:

Intent intent = new Intent(BROADCAST);  
        Bundle extras = new Bundle();  
        extras.putString("send_data", "test");  
        intent.putExtras(extras);  
        sendBroadcast(intent);

你的BroadcastReceiver:

private BroadcastReceiver myReceiver = new BroadcastReceiver() {

        public void onReceive(Context context, Intent intent) {
            // TODO Auto-generated method stub
             Bundle extras = intent.getExtras();
           if (extras != null){  
           {
                    rec_data = extras.getString("send_data");
            Log.d("Received Msg : ",rec_data);
            }
        }
    };

有关自定义广播的详细信息,请参阅Custom Intents and Broadcasting with Receivers

答案 1 :(得分:2)

在这里查看本教程,您将获得有关广播的所有帮助,包括如何从活动开始服务,反之亦然

http://www.vogella.de/articles/AndroidServices/article.html

答案 2 :(得分:0)

为此您必须广播接收者的意图,请参阅以下代码: -

Intent intent=new Intent();
getApplicationContext().sendBroadcast(intent);

您可以设置Intent的操作和其他属性,并可以使用Application上下文进行广播,无论您在此处设置的Intent操作是否必须在AndroidManifest.xml中使用receiver标记进行定义。

答案 3 :(得分:0)

检查这个答案:

https://stackoverflow.com/a/5473750/928361

我认为如果你没有在IntentFilter中指定任何内容,你需要告诉接收者类的意图。