Question

假设我们有一个如下字符串：

,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56

如何在Javascript中使用RegExp将其转换为以下字符串？

34,23,4,5,634,12,3,1234,54,123,43,2,3424,45,56

实际上，我想删除重复的项目，并且首先和最后,字符

Answer 1

[已编辑]要将这些转换为一组唯一数字，就像您实际要求的那样，请执行以下操作：

function scrapeNumbers(string) {
    var seen = {};
    var results = [];
    string.match(/\d+/g).forEach(function(x) {
        if (seen[x]===undefined)
            results.push(parseInt(x));
        seen[x] = true;
    });
    return results;
}

演示：

> scrapeNumbers(',1,22,333,22,,333,4,,,')
[1, 22, 333, 4]

如果您有一个Array.prototype.unique()原语，您可以将其写成一行：

yourString.match(/\d+/g).map(parseBase10).unique()

不幸的是，由于这个荒谬的难以追踪的错误，你需要有点冗长并定义自己的parseBase10 = function(n){return parseInt(n)}：javascript - Array#map and parseInt

Answer 2

不需要正则表达式。几点招数

text = ',34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56';
text = text.replace(/,+/g, ','); //replace two commas with one comma
text = text.replace(/^\s+|\s+$/g,''); //remove the spaces
textarray = text.split(","); // change them into array
textarray = textarray.filter(function(e){ return e.length});
console.log(textarray);                                       


// Now use a function to make the array unique
Array.prototype.unique = function(){
   var u = {}, a = [];
   for(var i = 0, l = this.length; i < l; ++i){
      if(this[i] in u)
         continue;
      a.push(this[i]);
      u[this[i]] = 1;
   }
   return a;
}

textarray = textarray.unique();
text = textarray.join(','); //combine them back to what you want
console.log(text);

Demo

如果你比jQuery更熟悉

text = text.replace(/,+/g, ',');
text = $.trim(text);
text = $.unique(text.split(",")).filter(function(e){ return e.length}).join(",");
console.log(text);

Demo

Answer 3

这样做：

function arrIndex(fnd, arr) {
    for (var len = arr.length, i = 0; i < len; i++) {
        if (i in arr && arr[i] === fnd) {
            return i;
        }
    }
    return -1;
}

function scrapeNumbers(str) {
    var arr = str.replace(/,+/g, ",").replace(/^,/, "").replace(/,$/, "").split(",");

    for (var i = 0, len = arr.length, rtn = []; i < len; i++) {
        if (i in arr && arrIndex(arr[i], rtn) == -1) {
            rtn.push(arr[i]);
        }
    }
    return rtn.join(",");
}

var str = ",,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56,,";

alert(scrapeNumbers(str));

这是jsFiddle

注意：我为更好的browser support

创建了自定义array.indexOf函数

使用Javascript中的RegExp在开始/结束时删除重复的逗号和额外的逗号，并删除重复的数字？

3 个答案:

Demo

Demo