Question

考虑从.NET Web服务返回的以下JSON（根据jsonlint有效）：

{"d":"{\"categories\":{\"category\":[{\"categoryID\":\"edNXeLBcDEa6sAFrxmjoXw\",\"categoryName\":\"Academics\",\"webSiteID\":\"jXKvJ3R85kiAodlhw06FjQ\",\"websiteName\":\"MySite\",\"departmentID\":\"FU0tEh2MCEu54qiVgBX6Yg\",\"departmentName\":\"WebServices\",\"departmentWebSite\":null,\"departmentLogo\":null},{\"categoryID\":\"9QcMMZjMo0G7kMM3kP7Apw\",\"categoryName\":\"Admissions\",\"webSiteID\":\"jXKvJ3R85kiAodlhw06FjQ\",\"websiteName\":\"MySite\",\"departmentID\":\"FU0tEh2MCEu54qiVgBX6Yg\",\"departmentName\":\"WebServices\",\"departmentWebSite\":null,\"departmentLogo\":null},{\"categoryID\":\"Tm207w31ZE6c39DJ1Juk2Q\",\"categoryName\":\"Webinars\",\"webSiteID\":\"jXKvJ3R85kiAodlhw06FjQ\",\"websiteName\":\"MySite\",\"departmentID\":\"FU0tEh2MCEu54qiVgBX6Yg\",\"departmentName\":\"WebServices\",\"departmentWebSite\":null,\"departmentLogo\":null}],\"metaData\":{\"recordCount\":\"3\",\"pageIndex\":\"0\",\"pageSize\":\"0\"}}}"}

使用序列化JSON执行以下操作可以正常工作：

NSDictionary *d = [jsonResults objectForKey:@"d"];

这使得“d”的值：

{"categories":{"category":[{"categoryID":"edNXeLBcDEa6sAFrxmjoXw","categoryName":"Academics","webSiteID":"jXKvJ3R85kiAodlhw06FjQ","websiteName":"MySite","departmentID":"FU0tEh2MCEu54qiVgBX6Yg","departmentName":"WebServices","departmentWebSite":null,"departmentLogo":null},{"categoryID":"9QcMMZjMo0G7kMM3kP7Apw","categoryName":"Admissions","webSiteID":"jXKvJ3R85kiAodlhw06FjQ","websiteName":"MySite","departmentID":"FU0tEh2MCEu54qiVgBX6Yg","departmentName":"WebServices","departmentWebSite":null,"departmentLogo":null},{"categoryID":"Tm207w31ZE6c39DJ1Juk2Q","categoryName":"Webinars","webSiteID":"jXKvJ3R85kiAodlhw06FjQ","websiteName":"MySite","departmentID":"FU0tEh2MCEu54qiVgBX6Yg","departmentName":"WebServices","departmentWebSite":null,"departmentLogo":null}],"metaData":{"recordCount":"3","pageIndex":"0","pageSize":"0"}}}

如果我尝试调用“类别”的objectForKey，我只会收到“无法识别的选择器发送到实例”错误：

NSDictionary *categories = [d objectForKey:@"categories"];

我已经尝试了我能想到的一切，但我永远不会在这个JSON中获得超过一层的深度。我能用Java完成这项工作，但我正在尝试编写我的应用程序的iOS版本。由于我是Objective C的新手，我一定是缺少一些东西。有什么想法吗？

修改

这就是我在Java中用这个相同的JSON做的事情，如果这有帮助：

JSONArray arrCategories = null;
String strJson = JSON.postJSONData("http://mysite.com/webservice.asmx/GetCategories", "{'destinationId' : '" + DestinationID + "', 'orderBy' : 'categoryName', 'orderByDirection' : 'asc'}");
String d = new JSONObject(strJson).getString("d");
String strCategories = new JSONObject(d).getString("categories");
arrCategories = new JSONObject(strCategories).getJSONArray("category");
for(int i=0; i < arrCategories.length(); i++) {
    JSONObject objCategory = new JSONObject(arrCategories.getString(i));
    String categoryID = objCategory.getString("categoryID");
    String categoryName = objCategory.getString("categoryName");
}

Answer 1

您没有AJAX字符串。嗯，你这样做，但问题是，你里面有一个字符串。

d键以与以下相同的方式映射到字符串：

{name：“blah”}会将obj.name映射到字符串“blah”。

基本上，你需要解析JSON，然后在JSON中解析JSON。

无法将有效的JSON映射到Objective C类

1 个答案: