Question

好吧，我不得不重新解释我的问题，我的javascript代码无法继续下一步，即isset ['submit']它只是卡在那里。我真的希望有人在这里可以帮助我更正我的javascript代码，以便它成功调用isset并运行我的PHP代码将其添加到数据库。

我的PHP代码

if(isset($_POST['submit'])){

$firstname = mysql_escape_string($_POST['fname']);
$lastname = mysql_escape_string($_POST['lname']);
$age = mysql_escape_string($_POST['age']);
$gender = mysql_escape_string($_POST['gender']);
$email = mysql_escape_string($_POST['email']);
$password = mysql_escape_string($_POST['password']);
$nickname = mysql_escape_string($_POST['nickname']);
$regflag = 0;



$sql = "SELECT * FROM accounts";
$query = mysql_query($sql);
while($row = mysql_fetch_assoc($query))
{

        if($row['email'] == $email)
        {
            echo '<b> The email is already taken!</b>'; 
            $regflag = 0;
        }
        if($row['nickname'] == $nickname)
        {
            echo '&nbsp;<b>The nickname is already taken!</b>'; 
            $regflag = 0;
        }
}

if($regflag == 1)
{

    $regsql = "INSERT INTO accounts         VALUES('','$firstname','$lastname','$age','$gender','$email','$password','$nickname','MEMBER',now())";
    $query = mysql_query($regsql);
    echo '<body onLoad = "regsucess()"> </body>';
}

}

我的javascript代码

<script type = "text/javascript">
function validator(){

    if(!document.register.fname.value)
    {
    alert('You need to supply your first name.');
    document.register.fname.focus();
    return false;
    }
    if(!document.register.lname.value)
    {
    alert('You need to supply your last name.');
    document.register.lname.focus();
    return false;
    }
    if(!document.register.age.value)
    {
    alert('You need to supply your age.');
    document.register.age.focus();
    return false;
    }
    if(!document.register.email.value)
    {
    alert('You need to supply your email.');
    document.register.email.focus();
    return false;
    }
    if(!document.register.password.value)
    {
    alert('You need to supply your password.');
    document.register.password.focus();
    return false;
    }
    if(!document.register.nickname.value)
    {
    alert('You need to supply your nickname.');
    document.register.nickname.focus();
    return false;
    }


register.action = "register.php"
document.register.submit();
//alert("Congrats!");


}

Answer 1

为什么 register.action = "register.php"而不是 document.register.action = "register.php" ?? 如果你通过提交按钮或onsubmit来调用它，那么删除最后一行 document.register.submit();

最后，如果表单中有任何内容name="submit"，您将无法通过脚本调用提交事件

以下是我希望看到的内容

<script type = "text/javascript">
function validate(theForm){

  if(!theForm.fname.value) {
    alert('You need to supply your first name.');
    theForm.fname.focus();
    return false;
  }
  if(!theForm.lname.value) {
    alert('You need to supply your last name.');
    theForm.lname.focus();
    return false;
  }
  if(!theForm.age.value) {
    alert('You need to supply your age.');
    theForm.age.focus();
    return false;
  }
  if(!theForm.email.value) {
    alert('You need to supply your email.');
    theForm.email.focus();
    return false;
  }
  if(!theForm.password.value) {
    alert('You need to supply your password.');
    theForm.password.focus();
    return false;
  }
  if(!theForm.nickname.value) {
    alert('You need to supply your nickname.');
    theForm.nickname.focus();
    return false;
  }
  return true
}
</script>

使用

<form action="register.php" onsubmit="return validate(this)">

Answer 2

您应该复制（至少）您在PHP代码中使用Javascript的代码以插入数据库。事实上，插入的代码应该更加强硬 - Javascript的东西是接收通常的嫌疑人（错别字等）并为用户提供更好的体验。

确保Javascript代码不如PHP代码那么苛刻。

Answer 3

同意mplungjan。

你能告诉我们表单的HTML代码吗？也许提交输入的ID不同于“提交”。

JavaScript验证无法插入数据库

3 个答案: