Question

在我的机器上，Linux机器ulimit -n提供1024。这段代码：

from tempfile import mkstemp

for n in xrange(1024 + 1):
    f, path = mkstemp()

在最后一行循环失败：

Traceback (most recent call last):
  File "utest.py", line 4, in <module>
  File "/usr/lib/python2.7/tempfile.py", line 300, in mkstemp
  File "/usr/lib/python2.7/tempfile.py", line 235, in _mkstemp_inner
OSError: [Errno 24] Too many open files: '/tmp/tmpc5W3CF'
Error in sys.excepthook:
Traceback (most recent call last):
  File "/usr/lib/python2.7/dist-packages/apport_python_hook.py", line 64, in apport_excepthook
ImportError: No module named fileutils

好像我已经打开了许多文件 - 但type和f的{{1}}只是path和int所以我是不确定如何关闭我打开的每个文件。 如何从tempfile.mkstemp关闭文件？

Answer 1

由于mkstemp()返回原始文件描述符，您可以使用os.close()：

import os
from tempfile import mkstemp

for n in xrange(1024 + 1):
    f, path = mkstemp()
    # Do something with 'f'...
    os.close(f)

Answer 2

import tempfile
import os
for idx in xrange(1024 + 1):
    outfd, outsock_path = tempfile.mkstemp()
    outsock = os.fdopen(outfd,'w')
    outsock.close()

Answer 3

使用os.close()关闭文件描述符：

import os
from tempfile import mkstemp

# Open a file
fd, path = mkstemp()  

# Close opened file
os.close( fd )

如何从tempfile.mkstemp关闭文件？

3 个答案: