Question

所有

我有一个从数据库中获取日期（YYYY-MM-DD H：M：S）的方法，并使用日期字符串中的年，月和日组件创建一个URL。我的解决方案有效，但我想知道是否有更好的方法来做到这一点？凉爽的孩子们如何做到这一点？： - ）

谢谢！

   -(NSString *) prettyURLFrom:(NSString *)dateString{



    NSString * URLString = @"";
    NSString *URL = @"http://www.theblues.com/featured/article/";

    NSArray *myWords = [dateString componentsSeparatedByCharactersInSet:
                        [NSCharacterSet characterSetWithCharactersInString:@"-\" \" :"]
                        ];


    URLString = [NSString stringWithFormat:@"%@%@/%@/%@", 
                    URL,
                    [myWords objectAtIndex:1],
                    [myWords objectAtIndex:2],
                    [myWords objectAtIndex:0]];



    return URLString;


   }

Answer 1

如果您有NSDate个对象，则可以使用

NSDateComponents *components = [[NSCalendar currentCalendar] components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:date];

    NSInteger day = [components day];
    NSInteger month = [components month];
    NSInteger year = [components year];

NSString到NSDate

[NSDateFormatter setDefaultFormatterBehavior:NSDateFormatterBehavior10_4];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"YYYY-MM-DD HH:MM:SS"];

NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:@"1999-07-02 2:2:4"];

Answer 2

就像我在评论中所说的那样，我发现你传递的值很奇怪，并且当它们可能分别是NSDate和NSURL时，将值作为字符串返回。

我可能会这样做：

-(NSURL*)URLFromDate:(NSDate*)date
{
    // Assumes user uses a gregorian calendar
    NSDateComponents *dateComp = [[NSCalendar currentCalendar] components:(NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit) fromDate:date];

    return [NSURL URLWithString:[NSString stringWithFormat:@"http://www.theblues.com/featured/article/%li/%li/%li"
                                    , [dateComp year]
                                    , [dateComp month]
                                    , [dateComp day]]];
}

打破Objective-C中的字符串

2 个答案: