Question

由于我不是Php程序员，我不得不问你，我必须挑战调查目前受到攻击的一些来源。它的一些本地新闻网站内有自定义cms。它的phg mysql在共享linux主机环境下。

admin在登录表单中输入凭据时注册，这些凭据在db中检查如下：

<?php
    session_start();
        include 'db.php';

    $connection = mysql_connect($dbHost, $dbUser, $dbPass) or die(mysql_error());
    mysql_select_db($dbName, $connection) or die(mysql_error());

        $queryString = "SELECT * FROM `Admins` WHERE `username` = '$user_name' AND password='$password'";
        $safeSelect = mysql_real_escape_string($queryString);

        $query = "SELECT * FROM `Admins`
            WHERE `username` = '$user_name' AND password='$password'";
    $result = mysql_query($query, $connection) or die('error making query');
    $affected_rows = mysql_num_rows($result);

        if($affected_rows == 1) {
        //add the user to our session variables
    $_SESSION['username'] = $user_name;
    header("Location: http://www.mysite.com/admin/index.php");
        exit;
        //print 'allowed';
        }
    else {
        print 'access is not allowed !!!';
    }
?>

Auth.php

<?php
    session_start();
    include 'db.php';
    if (empty($_SESSION['username'])) {
        die('to access these page you have to be registered user.
        <a href="/admin/login.php">log in</a>');
    }
?>

此会话var用于整个管理区域以识别注册用户。管理员用户编辑并创建这样的新内容 edit.php

<?php
session_start();
include '/admin/db.php';
include '/admin/auth.php';
  ini_set("display_errors", 1);
    error_reporting(E_ALL);
    $dbcnx = mysql_connect('localhost', $dbUser, $dbPass);
    mysql_select_db($dbName);
    if (isset($_POST['submit'])):
        // content will be updated with these
        $id = $_POST['id'];
        $cats = $_POST['cats'];
        $newstext = $_POST['newstext'];

$sql = "UPDATE `News` SET
             `NewsText`='$newstext',
             `AID`='$aid',
         `imgID`='$imgID'
             WHERE `ID`='$id'";
 if (mysql_query($sql)) {
            echo('<p><b>content is succ. updated</b></p>');
        } else {
            die('<p>Error occured when updating content: ' .
                    mysql_error() . '</p>');
        }
else: // Allow user to edit content using ID=$id

            /* $aid = $_GET['aid']; */
             if (isset($_GET['id'])) {
                if (is_numeric($_GET['id']) == FALSE) {
                    echo "<h1>Page is not found</h1>";
                    session_destroy();
                return;
             }
                $id = $_GET['id'];
            }

$row = @mysql_query("SELECT `NewsText`, `Title`, `AID`, `imgID` FROM `News` WHERE `ID`='$id'");
            if (!$row) {
                die('<p>Db error: ' .
                        mysql_error() . '</p>');
            }
$row = mysql_fetch_array($row);
            $newstext = $row['NewsText'];
            $text = $row ['Title'];
            $authid = $row ['AID'];
            $imgID = $row ['imgID'];
            $newstext = htmlspecialchars($newstext);

//ommitting html form
?>

基本上我想问一下这里是否存在安全问题。

在这里找到解决方案 http://net.tutsplus.com/tutorials/php/why-you-should-be-using-phps-pdo-for-database-access/