Question

我对android / java有点新意。我试图将JSON值传递到列表中，然后传递到多维数组中。我没有太大的成功。

2个问题， 1）如何将json数组中的所有变量加载到children [] []中？ 2）如何在Log.i

中查看子项[] []

这是我的代码：

List<String> cList = new ArrayList<String>();
String customer_name, customer_title, customer_postal_code, customer_city, customer_state, customer_street_address;   
ArrayList<String> cTitle, cClubName, cPostalCode, cCity, cState, cStreet = new ArrayList<String>();    
public String[][] children = null;

// ... onCreate方法，HTTP连接，StringBuilder等。这些工作正常...... //将数据传递到数组

try{
    JSONArray jArray = new JSONArray(result);
    JSONObject jData=null;


String[][] children = new String[jArray.length()][6];

    for(int i=0;i<jArray.length();i++){


            jData = jArray.getJSONObject(i);

            customer_name=jData.getString("customer_name");     
            Log.i("JSON ", "customer_name LOG " + customer_name);
            cList.add(customer_name);

            customer_title=jData.getString("event_title");
            Log.i("JSON ", "customer_title LOG " + customer_title);
            cList.add(customer_title);

            customer_street_address=jData.getString("customer_street_address");
            Log.i("JSON ", "customer_Id LOG " + customer_street_address);
            cList.add(customer_street_address);


            customer_city=jData.getString("customer_city");
            Log.i("JSON ", "customer_city LOG " + customer_city);
            cList.add(customer_city);



            customer_state=jData.getString("customer_state");   
            Log.i("JSON ", "customer_state LOG " + customer_state);
            cList.add(customer_state);


            customer_postal_code=jData.getString("customer_postal_code");               
            Log.i("JSON ", "customer_postal_code LOG " + customer_postal_code);
            cList.add(customer_postal_code);

            for(int ic = 0; ic < cList.size(); ic++) {      
                Log.i("jData ", "length " + jData.length());

                children[i][ic] = (String) cList.get(ic);

            }

            Log.i("Child Array", "Children array LOG " + children);




    }


    }catch(JSONException e1){
        Toast.makeText(getBaseContext(), "No customers Found", Toast.LENGTH_LONG).show();
    }catch (ParseException e1){
        e1.printStackTrace();
    }

}

Answer 1

如果我正确理解您的代码，则不需要cList。这样的事情应该做的工作

String[][] children = new String[jArray.length()][6];

    for(int i=0;i<jArray.length();i++){

            jData = jArray.getJSONObject(i);

            customer_name=jData.getString("customer_name");     
            Log.i("JSON ", "customer_name LOG " + customer_name);
            children[i][0] = customer_name;


            customer_title=jData.getString("event_title");
            Log.i("JSON ", "customer_title LOG " + customer_title);
            children[i][1] = event_title;

            customer_street_address=jData.getString("customer_street_address");
            Log.i("JSON ", "customer_Id LOG " + customer_street_address);
            children[i][2] = customer_street_address;

            customer_city=jData.getString("customer_city");
            Log.i("JSON ", "customer_city LOG " + customer_city);
            children[i][3] = customer_city;

            customer_state=jData.getString("customer_state");   
            Log.i("JSON ", "customer_state LOG " + customer_state);
            children[i][4] = customer_state;


            customer_postal_code=jData.getString("customer_postal_code");               
            Log.i("JSON ", "customer_postal_code LOG " + customer_postal_code);
            children[i][5] = customer_postal_code;
    }

确保您的JSON数据格式正确，以避免异常。要查看子项[] []，您可以在多维数组上迭代两次并执行Log.i（“MyTag”，“Value：”+ children [i] [j]）;

Answer 2

String[][] data = new String[jsonArray.length][];

for(int i = 0; i<jsonArray.length; i++){
     data[i] = ((ArrayList)jsonArray).get(i).toArray(new String[((ArrayList)jsonArray).get(i).size])
}

用于在日志中打印

Log.d("array", data);

如何将JSON数组的结果传递到多维数组？

2 个答案: