Question

我有一个书籍数据库，其中包含与书籍相关的类别和标签。我正在尝试构建一个过滤器，让用户可以过滤多个类别或标签，并查看包含这些标签或类别的书籍。它适用于单个类别或标记，但如果由于按书籍ID分组而存在多个标记或类别，则它会崩溃。

SELECT books.id as id,title, sub_title,medium_image_url,
    amzn_url,amzn_review as review,SUBSTRING(kindle_price,2) as price,
    IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) AS rating ,
    categories.category as category,GROUP_CONCAT(DISTINCT categories.id SEPARATOR ", ") as all_cats 
    FROM books 
    JOIN combined_ratings ON books.id = combined_ratings.book_id JOIN book_categories ON books.id = book_categories.book_id 
    JOIN categories ON book_categories.category_id = categories.id 
    WHERE (SUBSTRING(kindle_price,2) >= 0 
    AND SUBSTRING(kindle_price,2) <= 12 
    AND kindle_price <> "") 
    AND (IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) >= 0 
    AND IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) <= 100) 
    GROUP BY id 
    ORDER BY price ASC, rating DESC

我尝试过使用GROUP_CONCAT和HAVING，我只是读了一下IN（），但我尝试了它并没有用。我现在真正需要做的就是做一些像IN（）的东西，任何建议？

编辑：我使用了这个并且能够获得单个类别的结果，但它只能运行一次...... 这有效......

AND FIND_IN_SET( categories.id, '6' ) > 0

这不是

AND FIND_IN_SET( categories.id, '6' ) > 0 AND FIND_IN_SET( categories.id, '5' ) > 0

如果我能够解决这个问题，那就解决了我的问题。

Answer 1

前一段时间有stackoverflow发布。请check it out。另一种方法是每次创建临时表并将所有标签和类别放在那里，然后进行连接。

Answer 2

我放弃了尝试单独使用JOIN并使用子查询。这对我有用，可能不太理想，但我现在可以根据需要过滤尽可能多的标签或类别。

SELECT id, title, author, image, sub_title, price, SUM(count) as count, rating FROM 
(
SELECT books.id as id, title, author, medium_image_url as image, sub_title, kindle_price as price, IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) as rating , COUNT( DISTINCT category_id ) AS count 
FROM book_categories 
JOIN books ON book_categories.book_id = books.id 
JOIN authors ON books.author_id = authors.id 
JOIN combined_ratings ON books.id = combined_ratings.book_id 
WHERE category_id = 5 
OR category_id = 6 
OR category_id = 12 
GROUP BY book_categories.book_id 
HAVING count >= 3 
UNION ALL 
SELECT books.id as id, title, author, medium_image_url as image, sub_title, kindle_price as price, IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) as rating , COUNT( DISTINCT tag_id ) AS count 
FROM book_tags JOIN books ON book_tags.book_id = books.id 
JOIN authors ON books.author_id = authors.id 
JOIN combined_ratings ON books.id = combined_ratings.book_id 
WHERE book_tags.tag_id = 22 
GROUP BY book_tags.book_id HAVING count >= 1 
) 
as b1 
WHERE (SUBSTRING(price,2) >= 0 
AND SUBSTRING(price,2) <= 20 AND price <> '') 
AND (rating >= 0 AND rating <= 100) 
GROUP BY id 
HAVING count = 4
ORDER BY price ASC, 
rating DESC

这通过检查是否存在任何标准的结果然后计算标准匹配数来起作用。在外部查询中，我将两个联合查询相加，并确定这些计数的SUM（）是否与参数总数相匹配。

在单个查询中评估特定的分组值？

2 个答案: