mysql正确构造一个select查询

Question

我有一个包含id和值的表。他们只是在一起。

ID  VALUE
1   value1
1   value2
2   value1
3   value2
3   value3
3   value4
4   value3
5   value1

假设我被赋予值“value2”和“value3”，我想选择与这些值匹配的ID（即3）

我可以

SELECT ID FROM table WHERE VALUE IN("value2", "value3")

但是，它返回的值也匹配任何一个。有没有办法只查询匹配这两个值的那些？

Answer 1

你应该使用GROUP BY和HAVING

SELECT ID FROM table WHERE VALUE IN("value2", "value3") GROUP BY ID HAVING COUNT(*) = 2

Answer 2

尝试以下方法：

SELECT id FROM table WHERE value = "value2" and id in (SELECT id FROM table WHERE value = "value3")

Answer 3

SELECT t1.id FROM table AS t1 JOIN table AS t2 ON t1.id=t2.id
  WHERE t1.value="value2" AND t2.value="value3"