在此查询中,我尝试将结果导出到csv ...但是我收到错误
错误:----每个派生表都必须有自己的别名
SELECT * INTO OUTFILE "c:/mydata.csv"
FROM (SELECT e.server,e.token,e.datetime,e.workstation,f.surname,f.forename,f.token
FROM statistic e, USER f
WHERE e.token=f.token);
答案 0 :(得分:1)
尝试为子选择定义别名:
SELECT * INTO OUTFILE "c:/mydata.csv"
FROM (SELECT e.server,e.token as stat_token,e.datetime,e.workstation,
f.surname,f.forename,f.token as user_token
FROM statistic e,
USER f
WHERE e.token=f.token) as server_statistics;