如何在批处理文件中获得两次差异?因为我想在HTML文件中打印它。
我认为这是可能的,但事实并非如此。
Set "tijd=%time%"
echo %tijd%
echo %time%-%tijd%
结果:
11:07:48,85
11:16:58,99-11:07:48,85
但我想要的是:
00:09:10,14
或9分10秒或550秒
答案 0 :(得分:55)
@echo off
rem Get start time:
for /F "tokens=1-4 delims=:.," %%a in ("%time%") do (
set /A "start=(((%%a*60)+1%%b %% 100)*60+1%%c %% 100)*100+1%%d %% 100"
)
rem Any process here...
rem Get end time:
for /F "tokens=1-4 delims=:.," %%a in ("%time%") do (
set /A "end=(((%%a*60)+1%%b %% 100)*60+1%%c %% 100)*100+1%%d %% 100"
)
rem Get elapsed time:
set /A elapsed=end-start
rem Show elapsed time:
set /A hh=elapsed/(60*60*100), rest=elapsed%%(60*60*100), mm=rest/(60*100), rest%%=60*100, ss=rest/100, cc=rest%%100
if %mm% lss 10 set mm=0%mm%
if %ss% lss 10 set ss=0%ss%
if %cc% lss 10 set cc=0%cc%
echo %hh%:%mm%:%ss%,%cc%
编辑2017-05-09: 添加更短的方法
我开发了一种更短的方法来获得相同的结果,所以我忍不住在这里发布它。用于分隔时间部分的两个for
命令和用于在结果中插入前导零的三个if
命令被两个长的算术表达式替换,甚至可以组合成一个更长的行。< / p>
该方法包括将带有“HH:MM:SS.CC”格式的时间的变量直接转换为将时间转换为厘秒所需的公式,相应地为下面给出的映射方案:
HH : MM : SS . CC
(((10 HH %%100)*60+1 MM %%100)*60+1 SS %%100)*100+1 CC %%100
也就是说,在开头插入(((10
,用%%100)*60+1
替换冒号,将点替换为%%100)*100+1
并在结尾插入%%100
;最后,将结果字符串计算为算术表达式。在时间变量中,有两个不同的子串需要替换,因此转换必须以两行完成。要获得已用时间,请使用(endTime)-(startTime)
表达式并替换同一行中的两个时间字符串。
编辑2017/06/14: 添加了区域设置独立调整
@echo off
setlocal EnableDelayedExpansion
set "startTime=%time: =0%"
set /P "=Any process here..."
set "endTime=%time: =0%"
rem Get elapsed time:
set "end=!endTime:%time:~8,1%=%%100)*100+1!" & set "start=!startTime:%time:~8,1%=%%100)*100+1!"
set /A "elap=((((10!end:%time:~2,1%=%%100)*60+1!%%100)-((((10!start:%time:~2,1%=%%100)*60+1!%%100)"
rem Convert elapsed time to HH:MM:SS:CC format:
set /A "cc=elap%%100+100,elap/=100,ss=elap%%60+100,elap/=60,mm=elap%%60+100,hh=elap/60+100"
echo Start: %startTime%
echo End: %endTime%
echo Elapsed: %hh:~1%%time:~2,1%%mm:~1%%time:~2,1%%ss:~1%%time:~8,1%%cc:~1%
您可以在this answer查看此方法的详细说明。
答案 1 :(得分:39)
在这里回答: How can I use a Windows batch file to measure the performance of console application?
批量“程序”下面应该做你想要的。请注意,它以厘秒而不是毫秒输出数据。使用命令的精度只有几厘秒。
以下是输出示例:
STARTTIME: 13:42:52,25
ENDTIME: 13:42:56,51
STARTTIME: 4937225 centiseconds
ENDTIME: 4937651 centiseconds
DURATION: 426 in centiseconds
00:00:04,26
这是批处理脚本:
@echo off
setlocal
rem The format of %TIME% is HH:MM:SS,CS for example 23:59:59,99
set STARTTIME=%TIME%
rem here begins the command you want to measure
dir /s > nul
rem here ends the command you want to measure
set ENDTIME=%TIME%
rem output as time
echo STARTTIME: %STARTTIME%
echo ENDTIME: %ENDTIME%
rem convert STARTTIME and ENDTIME to centiseconds
set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
set /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)
rem calculating the duratyion is easy
set /A DURATION=%ENDTIME%-%STARTTIME%
rem we might have measured the time inbetween days
if %ENDTIME% LSS %STARTTIME% set set /A DURATION=%STARTTIME%-%ENDTIME%
rem now break the centiseconds down to hors, minutes, seconds and the remaining centiseconds
set /A DURATIONH=%DURATION% / 360000
set /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
set /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
set /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)
rem some formatting
if %DURATIONH% LSS 10 set DURATIONH=0%DURATIONH%
if %DURATIONM% LSS 10 set DURATIONM=0%DURATIONM%
if %DURATIONS% LSS 10 set DURATIONS=0%DURATIONS%
if %DURATIONHS% LSS 10 set DURATIONHS=0%DURATIONHS%
rem outputing
echo STARTTIME: %STARTTIME% centiseconds
echo ENDTIME: %ENDTIME% centiseconds
echo DURATION: %DURATION% in centiseconds
echo %DURATIONH%:%DURATIONM%:%DURATIONS%,%DURATIONHS%
endlocal
goto :EOF
答案 2 :(得分:20)
Aacini代码的重新哈希,因为您很可能将开始时间设置为变量并希望将该数据保存为输出:
@echo off
rem ****************** MAIN CODE SECTION
set STARTTIME=%TIME%
rem Your code goes here (remove the ping line)
ping -n 4 -w 1 127.0.0.1 >NUL
set ENDTIME=%TIME%
rem ****************** END MAIN CODE SECTION
rem Change formatting for the start and end times
for /F "tokens=1-4 delims=:.," %%a in ("%STARTTIME%") do (
set /A "start=(((%%a*60)+1%%b %% 100)*60+1%%c %% 100)*100+1%%d %% 100"
)
for /F "tokens=1-4 delims=:.," %%a in ("%ENDTIME%") do (
set /A "end=(((%%a*60)+1%%b %% 100)*60+1%%c %% 100)*100+1%%d %% 100"
)
rem Calculate the elapsed time by subtracting values
set /A elapsed=end-start
rem Format the results for output
set /A hh=elapsed/(60*60*100), rest=elapsed%%(60*60*100), mm=rest/(60*100), rest%%=60*100, ss=rest/100, cc=rest%%100
if %hh% lss 10 set hh=0%hh%
if %mm% lss 10 set mm=0%mm%
if %ss% lss 10 set ss=0%ss%
if %cc% lss 10 set cc=0%cc%
set DURATION=%hh%:%mm%:%ss%,%cc%
echo Start : %STARTTIME%
echo Finish : %ENDTIME%
echo ---------------
echo Duration : %DURATION%
输出:
Start : 11:02:45.92
Finish : 11:02:48.98
---------------
Duration : 00:00:03,06
答案 3 :(得分:2)
根据以前的答案,这里有可重复使用的程序&#34;以及计算经过时间的用法示例:
@echo off
setlocal
set starttime=%TIME%
echo Start Time: %starttime%
REM ---------------------------------------------
REM --- PUT THE CODE YOU WANT TO MEASURE HERE ---
REM ---------------------------------------------
set endtime=%TIME%
echo End Time: %endtime%
call :elapsed_time %starttime% %endtime% duration
echo Duration: %duration%
endlocal
echo on & goto :eof
REM --- HELPER PROCEDURES ---
:time_to_centiseconds
:: %~1 - time
:: %~2 - centiseconds output variable
setlocal
set _time=%~1
for /F "tokens=1-4 delims=:.," %%a in ("%_time%") do (
set /A "_result=(((%%a*60)+1%%b %% 100)*60+1%%c %% 100)*100+1%%d %% 100"
)
endlocal & set %~2=%_result%
goto :eof
:centiseconds_to_time
:: %~1 - centiseconds
:: %~2 - time output variable
setlocal
set _centiseconds=%~1
rem now break the centiseconds down to hors, minutes, seconds and the remaining centiseconds
set /A _h=%_centiseconds% / 360000
set /A _m=(%_centiseconds% - %_h%*360000) / 6000
set /A _s=(%_centiseconds% - %_h%*360000 - %_m%*6000) / 100
set /A _hs=(%_centiseconds% - %_h%*360000 - %_m%*6000 - %_s%*100)
rem some formatting
if %_h% LSS 10 set _h=0%_h%
if %_m% LSS 10 set _m=0%_m%
if %_s% LSS 10 set _s=0%_s%
if %_hs% LSS 10 set _hs=0%_hs%
set _result=%_h%:%_m%:%_s%.%_hs%
endlocal & set %~2=%_result%
goto :eof
:elapsed_time
:: %~1 - time1 - start time
:: %~2 - time2 - end time
:: %~3 - elapsed time output
setlocal
set _time1=%~1
set _time2=%~2
call :time_to_centiseconds %_time1% _centi1
call :time_to_centiseconds %_time2% _centi2
set /A _duration=%_centi2%-%_centi1%
call :centiseconds_to_time %_duration% _result
endlocal & set %~3=%_result%
goto :eof
答案 4 :(得分:2)
修正了Gynnad领先的0
问题。我用两条线修好了
SET STARTTIME=%STARTTIME: =0%
SET ENDTIME=%ENDTIME: =0%
完整脚本(CalculateTime.cmd
):
@ECHO OFF
:: F U N C T I O N S
:__START_TIME_MEASURE
SET STARTTIME=%TIME%
SET STARTTIME=%STARTTIME: =0%
EXIT /B 0
:__STOP_TIME_MEASURE
SET ENDTIME=%TIME%
SET ENDTIME=%ENDTIME: =0%
SET /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
SET /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)
SET /A DURATION=%ENDTIME%-%STARTTIME%
IF %DURATION% == 0 SET TIMEDIFF=00:00:00,00 && EXIT /B 0
IF %ENDTIME% LSS %STARTTIME% SET /A DURATION=%STARTTIME%-%ENDTIME%
SET /A DURATIONH=%DURATION% / 360000
SET /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
SET /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
SET /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)
IF %DURATIONH% LSS 10 SET DURATIONH=0%DURATIONH%
IF %DURATIONM% LSS 10 SET DURATIONM=0%DURATIONM%
IF %DURATIONS% LSS 10 SET DURATIONS=0%DURATIONS%
IF %DURATIONHS% LSS 10 SET DURATIONHS=0%DURATIONHS%
SET TIMEDIFF=%DURATIONH%:%DURATIONM%:%DURATIONS%,%DURATIONHS%
EXIT /B 0
:: U S A G E
:: Start Measuring
CALL :__START_TIME_MEASURE
:: Print Message on Screen without Linefeed
ECHO|SET /P=Execute Job...
:: Some Time pending Jobs here
:: '> NUL 2>&1' Dont show any Messages or Errors on Screen
MyJob.exe > NUL 2>&1
:: Stop Measuring
CALL :__STOP_TIME_MEASURE
:: Finish the Message 'Execute Job...' and print measured Time
ECHO [Done] (%TIMEDIFF%)
:: Possible Result
:: Execute Job... [Done] (00:02:12,31)
:: Between 'Execute Job... ' and '[Done] (00:02:12,31)' the Job will be executed
答案 5 :(得分:2)
Aacini的最新代码展示了一种非常棒的变量替换方法 遗憾的是,它不是区域格式证明 - 它在很多层面都失败了 这是一个简短的修复方法,可以保持替换+数学方法的完整性:
@echo off
setlocal EnableDelayedExpansion
set "startTime=%time: =0%" & rem AveYo: fix single digit hour
set /P "=Any process here..."
set "endTime=%time: =0%" & rem AveYo: fix single digit hour
rem Aveyo: Regional format fix with just one aditional line
for /f "tokens=1-3 delims=0123456789" %%i in ("%endTime%") do set "COLON=%%i" & set "DOT=%%k"
rem Get elapsed time:
set "end=!endTime:%DOT%=%%100)*100+1!" & set "start=!startTime:%DOT%=%%100)*100+1!"
set /A "elap=((((10!end:%COLON%=%%100)*60+1!%%100)-((((10!start:%COLON%=%%100)*60+1!%%100)"
rem Aveyo: Fix 24 hours
set /A "elap=!elap:-=8640000-!"
rem Convert elapsed time to HH:MM:SS:CC format:
set /A "cc=elap%%100+100,elap/=100,ss=elap%%60+100,elap/=60,mm=elap%%60+100,hh=elap/60+100"
echo Start: %startTime%
echo End: %endTime%
echo Elapsed: %hh:~1%%COLON%%mm:~1%%COLON%%ss:~1%%DOT%%cc:~1% & rem AveYo: display as regional
pause
&#34;精益和意味着&#34;区域格式的定时器,24小时和混合输入支持
适应Aacini's替换方法正文,没有IF,只有一个FOR(我的区域修正)
1:文件 timer.bat 放在%PATH%或当前目录
的某处@echo off & rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!" & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof
用法:
计时器 &amp; echo start_cmds&amp;超时/ t 3&amp; echo end_cmds&amp; 计时器
计时器&amp; 计时器&#34; 23:23:23,00&#34;
计时器&#34; 23:23:23,00&#34; &安培;的计时器强>
计时器&#34; 13.23.23,00&#34; &安培; 计时器&#34; 03:03:03.00&#34;
计时器&amp; 计时器&#34; 0:00:00.00&#34;没有&amp; cmd / v:on / c echo直到午夜=!timer_end!
输入现在可以混合使用,对于那些不太可能,但在执行期间可能的时间格式更改
2:与批处理脚本捆绑在一起的函数:timer (下面的示例用法):
@echo off
set "TIMER=call :timer" & rem short macro
echo.
echo EXAMPLE:
call :timer
timeout /t 3 >nul & rem Any process here..
call :timer
echo.
echo SHORT MACRO:
%TIMER% & timeout /t 1 & %TIMER%
echo.
echo TEST INPUT:
set "start=22:04:04.58"
set "end=04.22.44,22"
echo %start% ~ start & echo %end% ~ end
call :timer "%start%"
call :timer "%end%"
echo.
%TIMER% & %TIMER% "00:00:00.00" no
echo UNTIL MIDNIGHT: %timer_end%
echo.
pause
exit /b
::测试它,复制粘贴代码段上方和下方
rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support
:timer Usage " call :timer [input - optional] [no - optional]" :i Result printed on second call, saved to timer_end
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!" & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof
答案 6 :(得分:2)
这是我尝试批量测量时差。
它尊重%TIME%的区域格式,而不对时间和小数分隔符的字符类型进行任何假设。
代码已注释,但我也会在此处进行描述。
它非常灵活,因此它也可用于标准化非标准时间值
主要功能:timediff
:: timediff
:: Input and output format is the same format as %TIME%
:: If EndTime is less than StartTime then:
:: EndTime will be treated as a time in the next day
:: in that case, function measures time difference between a maximum distance of 24 hours minus 1 centisecond
:: time elements can have values greater than their standard maximum value ex: 12:247:853.5214
:: provided than the total represented time does not exceed 24*360000 centiseconds
:: otherwise the result will not be meaningful.
:: If EndTime is greater than or equals to StartTime then:
:: No formal limitation applies to the value of elements,
:: except that total represented time can not exceed 2147483647 centiseconds.
:timediff <outDiff> <inStartTime> <inEndTime>
(
setlocal EnableDelayedExpansion
set "Input=!%~2! !%~3!"
for /F "tokens=1,3 delims=0123456789 " %%A in ("!Input!") do set "time.delims=%%A%%B "
)
for /F "tokens=1-8 delims=%time.delims%" %%a in ("%Input%") do (
for %%A in ("@h1=%%a" "@m1=%%b" "@s1=%%c" "@c1=%%d" "@h2=%%e" "@m2=%%f" "@s2=%%g" "@c2=%%h") do (
for /F "tokens=1,2 delims==" %%A in ("%%~A") do (
for /F "tokens=* delims=0" %%B in ("%%B") do set "%%A=%%B"
)
)
set /a "@d=(@h2-@h1)*360000+(@m2-@m1)*6000+(@s2-@s1)*100+(@c2-@c1), @sign=(@d>>31)&1, @d+=(@sign*24*360000), @h=(@d/360000), @d%%=360000, @m=@d/6000, @d%%=6000, @s=@d/100, @c=@d%%100"
)
(
if %@h% LEQ 9 set "@h=0%@h%"
if %@m% LEQ 9 set "@m=0%@m%"
if %@s% LEQ 9 set "@s=0%@s%"
if %@c% LEQ 9 set "@c=0%@c%"
)
(
endlocal
set "%~1=%@h%%time.delims:~0,1%%@m%%time.delims:~0,1%%@s%%time.delims:~1,1%%@c%"
exit /b
)
示例:强>
@echo off
setlocal EnableExtensions
set "TIME="
set "Start=%TIME%"
REM Do some stuff here...
set "End=%TIME%"
call :timediff Elapsed Start End
echo Elapsed Time: %Elapsed%
pause
exit /b
:: put the :timediff function here
<小时/> 解释:timediff功能:
function prototype :timediff <outDiff> <inStartTime> <inEndTime>
输入和输出格式与%TIME%
的格式相同从左到右需要3个参数:
Param1:要将结果保存到的环境变量的名称
Param2:要传递给包含StartTime字符串的函数的环境变量的名称
Param3:要传递给包含EndTime字符串的函数的环境变量的名称
如果EndTime小于StartTime,则:
<小时/> 包含字面值和非标准时间值的更多示例
@echo off
setlocal EnableExtensions
set "start=23:57:33,12"
set "end=00:02:19,41"
call :timediff dif start end
echo Start Time: %start%
echo End Time: %end%
echo,
echo Difference: %dif%
echo,
pause
exit /b
:: put the :timediff function here
Start Time: 23:57:33,12 End Time: 00:02:19,41 Difference: 00:04:46,29
@echo off
setlocal EnableExtensions
set "start=00:00:00.00"
set "end=27:2457:433.85935"
call :timediff normalized start end
echo,
echo %end% is equivalent to %normalized%
echo,
pause
exit /b
:: put the :timediff function here
27:2457:433.85935 is equivalent to 68:18:32.35
@echo off
setlocal EnableExtensions
set "start=00:00:00.00"
set "end=00:00:00.2147483647"
call :timediff normalized start end
echo,
echo 2147483647 centiseconds equals to %normalized%
echo,
pause
exit /b
:: put the :timediff function here
2147483647 centiseconds equals to 5965:13:56.47
答案 7 :(得分:1)
使用具有自定义测量单位或格式化的单一功能。 每次调用函数时都没有参数,我们重新启动了初始时间。
@ECHO OFF
ECHO.
ECHO DEMO timer function
ECHO --------------------
SET DELAY=4
:: First we call the function without any parameters to set the starting time
CALL:timer
:: We put some code we want to measure
ECHO.
ECHO Making some delay, please wait...
ECHO.
ping -n %DELAY% -w 1 127.0.0.1 >NUL
:: Now we call the function again with the desired parameters
CALL:timer elapsed_time
ECHO by Default : %elapsed_time%
CALL:timer elapsed_time "s"
ECHO in Seconds : %elapsed_time%
CALL:timer elapsed_time "anything"
ECHO Formatted : %elapsed_time% (HH:MM:SS.CS)
ECHO.
PAUSE
:: Elapsed Time Function
:: -----------------------------------------------------------------------
:: The returned value is in centiseconds, unless you enter the parameters
:: to be in another unit of measure or with formatted
::
:: Parameters:
:: <return> the returned value
:: [formatted] s (for seconds), m (for minutes), h (for hours)
:: anything else for formatted output
:: -----------------------------------------------------------------------
:timer <return> [formatted]
SetLocal EnableExtensions EnableDelayedExpansion
SET _t=%time%
SET _t=%_t::0=: %
SET _t=%_t:,0=, %
SET _t=%_t:.0=. %
SET _t=%_t:~0,2% * 360000 + %_t:~3,2% * 6000 + %_t:~6,2% * 100 + %_t:~9,2%
SET /A _t=%_t%
:: If we call the function without parameters is defined initial time
SET _r=%~1
IF NOT DEFINED _r (
EndLocal & SET TIMER_START_TIME=%_t% & GOTO :EOF
)
SET /A _t=%_t% - %TIMER_START_TIME%
:: In the case of wanting a formatted output
SET _f=%~2
IF DEFINED _f (
IF "%_f%" == "s" (
SET /A "_t=%_t% / 100"
) ELSE (
IF "%_f%" == "m" (
SET /A "_t=%_t% / 6000"
) ELSE (
IF "%_f%" == "h" (
SET /A "_t=%_t% / 360000"
) ELSE (
SET /A "_h=%_t% / 360000"
SET /A "_m=(%_t% - !_h! * 360000) / 6000"
SET /A "_s=(%_t% - !_h! * 360000 - !_m! * 6000) / 100"
SET /A "_cs=(%_t% - !_h! * 360000 - !_m! * 6000 - !_s! * 100)"
IF !_h! LSS 10 SET "_h=0!_h!"
IF !_m! LSS 10 SET "_m=0!_m!"
IF !_s! LSS 10 SET "_s=0!_s!"
IF !_cs! LSS 10 SET "_cs=0!_cs!"
SET "_t=!_h!:!_m!:!_s!.!_cs!"
SET "_t=!_t:00:=!"
)
)
)
)
EndLocal & SET %~1=%_t%
goto :EOF
延迟94秒的测试
DEMO timer function
--------------------
Making some delay, please wait...
by Default : 9404
in Seconds : 94
Formatted : 01:34.05 (HH:MM:SS.CS)
Presione una tecla para continuar . . .
答案 8 :(得分:1)
如果您不介意在批处理脚本中使用Powershell:
@echo off
set start_date=%date% %time%
:: Simulate some type of processing using ping
ping 127.0.0.1
set end_date=%date% %time%
powershell -command "&{$start_date1 = [datetime]::parse('%start_date%'); $end_date1 = [datetime]::parse('%date% %time%'); echo (-join('Duration in seconds: ', ($end_date1 - $start_date1).TotalSeconds)); }"
答案 9 :(得分:0)
CMD没有时间算法。但是,以下代码提供了一种解决方法:
set vid_time=11:07:48
set srt_time=11:16:58
REM Get time difference
set length=%vid_time%
for /f "tokens=1-3 delims=:" %i in ("%length%") do (
set /a h=%i*3600
set /a m=%j*60
set /a s=%k
)
set /a t1=!h!+!m!+!s!
set length=%srt_time%
for /f "tokens=1-3 delims=:" %i in ("%length%") do (
set /a h=%i*3600
set /a m=%j*60
set /a s=%k
)
set /a t2=!h!+!m!+!s!
cls
set /a diff=!t2!-!t1!
以上代码以秒为单位给出差异。要以hh:mm:ss格式显示,请使用以下代码:
set ss=!diff!
set /a hh=!ss!/3600 >nul
set /a mm="(!ss!-3600*!hh!)/60" >nul
set /a ss="(!ss!-3600*!hh!)-!mm!*60" >nul
set "hh=0!hh!" & set "mm=0!mm!" & set "ss=0!ss!"
echo|set /p=!hh:~-2!:!mm:~-2!:!ss:~-2!
答案 10 :(得分:0)
@echo off
set START=23:05:15
set END=07:02:05
set options="tokens=1-4 delims=:."
for /f %options% %%a in ("%start%") do set start_h=%%a&set /a start_m=100%%b %% 100&set /a start_s=100%%c %% 100&set /a start_ms=100%%d %% 100
for /f %options% %%a in ("%end%") do set end_h=%%a&set /a end_m=100%%b %% 100&set /a end_s=100%%c %% 100&set /a end_ms=100%%d %% 100
set /a hours=%end_h%-%start_h%
set /a mins=%end_m%-%start_m%
set /a secs=%end_s%-%start_s%
set /a ms=%end_ms%-%start_ms%
if %hours% lss 0 set /a hours = 24%hours%
if %mins% lss 0 set /a hours = %hours% - 1 & set /a mins = 60%mins%
if %secs% lss 0 set /a mins = %mins% - 1 & set /a secs = 60%secs%
if %ms% lss 0 set /a secs = %secs% - 1 & set /a ms = 100%ms%
if 1%ms% lss 100 set ms=0%ms%
set hours=0%hours%
set hours=%hours:~-2%
set mins=0%mins%
set mins=%mins:~-2%
set secs=0%secs%
set secs=%secs:~-2%
set /a totalsecs = %hours%*3600 + %mins%*60 + %secs%
echo Command took %hours%:%mins%:%secs%.%ms% (%totalsecs%.%ms%s total)
echo %date% %start% - %end% ( %hours%:%mins%:%secs% )
pause