Question

我有这样的数据：

Team | goal
a    | 5
b    | 8
a    | 5
f    | 8
c    | 5
a    | 3
g    | 5
d    | 8
a    | 5
e    | 4
a    | 9
a    | 8
b    | 2
c    | 3
f    | 1

我想让select table像这样：
例如：

Team   | sum(goal)
a      |  14
b      |  13
c      |  12
d      |  11
others | sum(outside limit 0,4)

所以我想列出他的总进球前4名球队
并将所有外部限制返回到一个名为“其他”的记录中（将前4名以外的其他球队的目标相加）

a，b，c，d尚未定义，请使用select , order, and limit to get TOP 4 Goal

Answer 1

我不确定你的意思是“外限0,4”。但您可以使用Union查询：

如下所示：

select Team,sum(goal) as goal  from table where Team in('a','b','c','d') group by  Team 
union
select 'Others' as Team ,sum(goal) as goal  table  where Team not in('a','b','c','d') 
group by  1

Answer 2

选择前4名球队的查询将如下： -

select `Team`, sum(`goal`) as goals  
from table_name 
order by goals desc limit 4;

对于其他团队，那么top $ query将是这样的

select `Team`, sum(`goal`) as goals  
from table_name 
order by goals desc limit 4,10;

（我不知道你的队伍总数，所以我把10作为参考）

Answer 3

联盟加入的两个查询将给出所需的结果：

( SELECT team AS team,SUM(goal) AS goals 
  FROM table
  GROUP BY 1 
  LIMIT 4 )
UNION
( SELECT 'Other',SUM(other.goals) FROM 
  ( SELECT team AS team,SUM(goal) AS goals 
    FROM table 
    GROUP BY 1 
    LIMIT 5,999999 ) other
)

如何选择带限制的表，并使用MYSQL将外部限制返回到名为“other”的记录中

3 个答案: