合并列表python中的所有元素

Question

我有一个字符串列表，如：

s = [("abc","bcd","cde"),("123","3r4","32f")]

现在我想将其转换为以下内容：

output = ["abcbcdcde","1233r432f"]

这样做的pythonic方法是什么？ 感谢

Answer 1

>>> [''.join(x) for x in s]
['abcbcdcde', '1233r432f']

Answer 2

>>> map(''.join, s)
['abcbcdcde', '1233r432f']

应该这样做

Answer 3

output = []
for grp in s:
    output.append(''.join(grp))

Answer 4

这个怎么样：

>>> map(lambda x: ''.join(x), s)
['abcbcdcde', '1233r432f']

Answer 5

不是一个真正的答案，只是想检查一下，还有什么关于reduce和operator.add，我读到它们会以这样的方式表现得非常快速有效，或者我错了吗？

s = [("abc","bcd","cde"),("123","3r4","32f")]

from operator import add

[reduce(add, x) for x in s]