Question

尝试选择同一客户的所有记录，但地址不同的记录。

所以我稍后可以让用户选择Bob Yonkers，然后选择将Bob的所有记录更新为特定地址。所以我想展示所有可用的记录。

数据示例：

CUSTOMER_NAME, CUSTOMER_ADDRESS
Bob Yonkers  , 42 Satellite Cir
Bob Yonkers  , 667 Orbit St
Bob Yonkers  , 42 Satellite Cir
Bob Yonkers  , 667 Orbit St
David Boom   , 5959 Bush Ave
David Boom   , 5959 Bush Ave
David Boom   , 5959 Bush Ave
David Boom   , 5959 Bush Ave
David Boom   , 5959 Bush Ave
Ruby Tuesday , 123 Highway Ln Apt#1
Ruby Tuesday , 123 Highway Ln
David Boom   ,5959 Bush Ave
David Boom   ,5959 Bush Ave
David Boom   ,5959 Bush Ave

因此查询会带回这些结果......

结果示例：

CUSTOMER_NAME, CUSTOMER_ADDRESS
Bob Yonkers  , 42 Satellite Cir
Bob Yonkers  , 667 Orbit St
Ruby Tuesday , 123 Highway Ln Apt#1
Ruby Tuesday , 123 Highway Ln

任何帮助都将不胜感激。

Answer 1

SELECT * 
FROM [table] t1
INNER JOIN [table] t2 ON t1.Name=t2.Name AND t1.Address<>t2.Address

Answer 2

这是乔尔的改进：

SELECT distinct t1.* 
FROM [table] t1
INNER JOIN [table] t2 ON t1.Name=t2.Name AND t1.Address<>t2.Address

Answer 3

尝试一下......

select * from (select count(customername) as ct, customername, address from table group by customername, address) t1
where t1.ct>1

Answer 4

这引起了我的兴趣，因为一位朋友问我类似的东西。下面的查询将解决问题，尽管效率不高：

mysql> select DISTINCT CUSTOMER_NAME,CUSTOMER_ADDRESS from CUST_ADDR where CUSTOMER_NAME in (select CUSTOMER_NAME from CUST_ADDR GROUP BY CUSTOMER_NAME HAVING COUNT(DISTINCT CUSTOMER_ADDRESS) > 1 );



+---------------+----------------------+
| CUSTOMER_NAME | CUSTOMER_ADDRESS     |
+---------------+----------------------+
| Bob Yonkers   | 42 Satellite Cir     |
| Bob Yonkers   | 667 Orbit St         |
| Ruby Tuesday  | 123 Highway Ln Apt#1 |
| Ruby Tuesday  | 123 Highway Ln       |
+---------------+----------------------+
4 rows in set (0.01 sec)

选择相同的客户名称，但具有不同的客户地址

4 个答案: