Question

我只是学习如何将sql查询转换为关系代数，反之亦然。

Customer(customer_name, customer_street, customer_city)
Loan(loan_number, branch_name, amount)
Borrower(customer_name, loan_number)
Account(account_number, branch_name, balance)
Depositor(customer_name, account_number)

我想找到住在费尔法克斯的客户，有贷款，但没有银行账户。

CustomersInFFX = PROJECT customer_name (SELECT customer_city = 'Fairfax'(Customer))
LoanOwners = (CustomersInFFX NATURAL JOIN Borrower NATURAL JOIN Loan)
AccountHolders = (Depositor NATURAL JOIN ACCOUNT)
PROJECT customer_name (LoanOwners - AccountHolders)

这有意义吗？

* SELECT：σ，PROJECT：π，NATURAL JOIN：⋈

Answer 1

这是我尝试使用标准SQL：

WITH CustomersInFFX 
     AS 
     (
      SELECT *
        FROM Customer
       WHERE customer_city = 'Fairfax'
     ),
     LoanOwners 
     AS
     (
      SELECT * 
        FROM CustomersInFFX 
             NATURAL JOIN Borrower 
             NATURAL JOIN Loan
     ),
     AccountHolders
     AS
     (
      SELECT *
        FROM Depositor 
             NATURAL JOIN ACCOUNT
     )
SELECT *
  FROM LoanOwners
EXCEPT CORRESPONDING DISTINCT
SELECT *
  FROM AccountHolders;

但是，这仅在LoanOwners和AccountHolders表具有相同数量的属性且每个具有相同名称的情况下才有效。情况不太可能如此，因此您只需要投射（SELECT）所需的属性，例如。

SELECT customer_name
  FROM LoanOwners
EXCEPT DISTINCT
SELECT customer_name
  FROM AccountHolders;

将SQL转换为关系代数

1 个答案: