Question

我尝试将Json Datas插入sqlite数据库。我从另一个类获取数据并且它们在字典中（responce.item）但我无法插入数据库。我收到了这样的错误：无法识别的选择器发送到实例。我怎么解决这个问题？我的方法如下。感谢您的回复。

已修改的代码：

-(void)processDoneWithRequestName:(NSString*)tagName{

sqlite3_stmt *stmt=nil;
sqlite3 *cruddb;

const char *sql = "INSERT INTO LabUpdate (IsSuccess, ProducerId, Latitude, Longitude, Altitude, Slope, SampleDate, PackageNo, Status, Description) VALUES (?,?,?,?,?,?,?,?,?,?)";            

//NSArray *pathsArray=NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask,YES);
NSString *doumentDirectoryPath=@"/Users/ds/Desktop/SqliteTest/SqliteTest";
NSString *cruddatabase=[doumentDirectoryPath stringByAppendingPathComponent:@"SqliteTestDb.sqlite"];

if ([tagName isEqualToString:Logins]) {

    int keys = [[response.item objectForKey:@"Lipton"] count];
    NSLog(@"count %i",keys);
    for (int i=0; i<keys; i++)
    {

        NSString *str1 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"IsSuccess"];
        NSString *str2 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"ProducerId"];
        NSString *str3 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Latitude"];
        NSString *str4 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Longitude"];
        NSString *str5 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Altitude"];
        NSString *str6 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Slope"];
        NSString *str7 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"SampleDate"];
        NSString *str8 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"PackageNo"];
        NSString *str9 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Status"];
        NSString *str10 =[[[response.item objectForKey:@"Lipton"] objectAtIndex:i]objectForKey:@"Description"];
        NSLog(@"str1 %@",str1);
        NSLog(@"str2 %@",str2);
        NSLog(@"str3 %@",str3);
        NSLog(@"str4 %@",str4);
        NSLog(@"str5 %@",str5);
        NSLog(@"str6 %@",str6);
        NSLog(@"str7 %@",str7);
        NSLog(@"str8 %@",str8);
        NSLog(@"str9 %@",str9);
        NSLog(@"str10 %@",str10);




        sqlite3_open([cruddatabase UTF8String], &cruddb);
        sqlite3_prepare_v2(cruddb, sql, 1, &stmt, NULL);
        sqlite3_bind_int(stmt, 1, [str1 integerValue]);
        sqlite3_bind_int(stmt, 2, [str2 integerValue]);
        sqlite3_bind_double(stmt, 3, [str3 floatValue]);
        sqlite3_bind_double(stmt, 4, [str4 floatValue]);
        sqlite3_bind_double(stmt, 5, [str5 floatValue]);
        sqlite3_bind_double(stmt, 6, [str6 floatValue]);
        sqlite3_bind_text(stmt, 7, [str7 UTF8String], -1, SQLITE_TRANSIENT);
        sqlite3_bind_int(stmt, 8, [str8 integerValue]);
        sqlite3_bind_int(stmt, 9, [str9 integerValue]);
        sqlite3_bind_text(stmt, 10, [str10 UTF8String], -1, SQLITE_TRANSIENT);


        sqlite3_step(stmt);
        sqlite3_finalize(stmt);
        sqlite3_close(cruddb); 



    }



}

}

Answer 1

该错误表示该对象为NSArray而不是NSDictionary。您可以使用-objectAtIndex:访问字典对象。

编辑：很难从你提供的信息中得知，但请尝试更改此行：

int keys = [[response.item objectForKey:@"Lipton"] count];

到此：

int keys = [[[response.item objectForKey:@"Lipton"] objectAtIndex:0] count];

或：

int keys = [[[response.item objectAtIndex:0] objectForKey:@"Lipton"] count];

就像我说的，如果没有更多的信息，我无法给出决定性的答案。

- [__ NSArrayM objectForKey：]：无法识别的选择器发送到目标c中的实例错误

1 个答案: