Question

有这个查询：

SELECT HOUR( DATE ) AS hr, COUNT( * ) AS cnt
FROM users
GROUP BY hr
ORDER BY cnt DESC

DATE是DATETIME字段，上面的查询显示了日期字段中最常见的小时数。

我正在努力改进它，但不知道该怎么做，我希望按工作日和每周工作时间分解到最常见的时间。

Answer 1

如果下面有效，请告诉我：

SELECT dayname(DATE) as week_day,HOUR( DATE ) AS hr, COUNT( * ) AS cnt 
FROM users 
GROUP BY week_day, hr ORDER BY cnt DESC

Answer 2

尝试此查询 -

SELECT
  DAYOFWEEK(DATE) AS wd,
  HOUR(DATE) AS hr,
  COUNT(*) AS cnt
FROM 
 users
GROUP BY
  wd, hr
ORDER BY
  cnt DESC

SELECT
  DATE_FORMAT(DATE, '%a') AS wd, -- or DATE_FORMAT(DATE, '%W')
  HOUR(DATE) AS hr,
  COUNT(*) AS cnt
FROM 
 users
GROUP BY
  wd, hr
ORDER BY
  cnt DESC

最常见的工作日查询

2 个答案: