Question

因此，对于pygame，你有一个while循环连续循环，然后你的事件处理程序在for循环中，然后是你想要连续执行的代码。

我需要在while循环中执行一行代码之后处理一个事件，尽管它们相互影响，但我还需要在行之前处理不同的事件。

如何在我的主while循环中处理一组事件，执行一些代码，然后处理另一组事件？

Answer 1

解决。

我在用户事件处理程序中设置了一个等于1的变量，然后在我需要执行代码的地方，我检查变量是否等于1，如果是，我执行了我的代码并设置了变量回到0。

好东西。

这是我的代码，如果有人想帮我找到更好的解决方案;）（有点长）：

uif = "images/userGray.png"
bif = "images/bg.jpg"
cif = "images/chair3.png"
i = 0
playerX = 1
playerY = 1
pX = 1
pY = 1
bX = 0
bY = 0
moveX = 0
moveY = 0
windowX = 640
windowY = 480
lowerY = 1024
lowerX = 1024
bullets = []
x = 0
y = 0
rotate = False

objects = []

objects.append([256,260,410,511])

import pygame, sys
from pygame.locals import *

pygame.init()

screen = pygame.display.set_mode((640,480),0,32)

background = pygame.image.load(bif).convert()
user = pygame.image.load(uif).convert_alpha()
chair = pygame.image.load(cif).convert_alpha()
chair1 = pygame.image.load(cif).convert_alpha()

pygame.time.set_timer(USEREVENT + 1, 100)

def shoot(inLoc, clLoc, weapon):
    bulletId = len(bullets)
    bullets[bulletId] = [inLoc, clLoc, 200, 3]

moveSpeed = .1

while True:



    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        if event.type == USEREVENT + 1:
            rotate = True;
        if event.type == KEYDOWN:
            if event.key == K_LEFT or event.key == K_a:
                moveX = -1*moveSpeed
            elif event.key == K_RIGHT or event.key == K_d:
                moveX = moveSpeed
            if event.key == K_DOWN or event.key == K_s:
                moveY = moveSpeed
            elif event.key == K_UP or event.key == K_w:
                moveY = -1*moveSpeed
        if event.type == KEYUP:
            if event.key == K_LEFT or event.key == K_a or event.key == K_RIGHT or event.key == K_d:
                moveX = 0
            if event.key == K_DOWN or event.key == K_s or event.key == K_UP or event.key == K_w:
                moveY = 0

    dontMoveX = 0
    dontMoveY = 0

    for obj in objects:

        if playerX + moveX > obj[0]-user.get_width() and playerX + moveX < obj[1] and playerY + moveY > obj[2]-user.get_height() and playerY + moveY < obj[3]:
            if playerY + moveY == obj[2]-user.get_height()-1 or playerY + moveY == obj[3]+1:
                dontMoveX = 0
            else:
                dontMoveX = 1

        if playerX + moveX > obj[0]-user.get_width() and playerX + moveX < obj[1] and playerY + moveY > obj[2]-user.get_height() and playerY + moveY < obj[3]:
            if playerX + moveX == obj[0]-user.get_width()-1 or playerX + moveX == obj[1]+1:
                dontMoveY = 0
            else:
                dontMoveY = 1

    if dontMoveX == 0:
        playerX += moveX

        if (playerX >= 0 and playerX <= windowX/2) or (playerX >= lowerX-(windowX/2) and playerX <= lowerX-user.get_width()):
            pX+=moveX
        if playerX > windowX/2 and playerX < lowerX-(windowX/2):
            bX+=-1*moveX

    if dontMoveY == 0:
        playerY += moveY

        if (playerY >= 0 and playerY <= windowY/2) or (playerY >= lowerY-(windowY/2) and playerY <= lowerY-user.get_width()):
            pY+=moveY
        if playerY > windowY/2 and playerY < lowerY-(windowY/2):
            bY+=-1*moveY

    screen.blit(background,(bX,bY))



    screen.blit(user,(pX,pY))


    pygame.mouse.set_visible(False);

    if rotate == True:    

        if i < 360:
            i = i + 18
        else:
            i = 0

        orig_chair_rect = chair.get_rect()
        chair1 = pygame.transform.rotate(chair, i);
        rot_chair_rect = orig_chair_rect.copy()
        rot_chair_rect.center = chair1.get_rect().center
        chair1 = chair1.subsurface(rot_chair_rect).copy()

        rotate = False

    x,y = pygame.mouse.get_pos()
    x -= chair.get_width()/2
    y -= chair.get_height()/2

    screen.blit(chair1,(x,y))

    pygame.display.update()

通过循环运行中途检查事件？

1 个答案: