Question

如何在uitableviews中的对象之间传递给我的详细视图？我已经设置了一个条件推送，正如你在我的方法中看到的那样：

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{

    Budget * tempBudget = [self.budgetPlan.budgets objectAtIndex:indexPath.row];

    NSString *targetViewControllerIdentifier = nil;
    if (tempBudget.hasBeenInitialized != true) {
        targetViewControllerIdentifier = @"budgetInitializerView";
        UIViewController *vc = [self.storyboard instantiateViewControllerWithIdentifier:targetViewControllerIdentifier];
        [self.navigationController pushViewController:vc animated:YES];

        // how do I pass the tempBudget to the pushed view?


    } else {
        targetViewControllerIdentifier = @"budgetDetailsView";
        UIViewController *vc = [self.storyboard instantiateViewControllerWithIdentifier:targetViewControllerIdentifier];
        [self.navigationController pushViewController:vc animated:YES];

        // how do I pass the tempBudget to the pushed view?

    }
}

我遇到了UIViewController *vc = [self.storyboard instantiateViewControllerWithIdentifier:targetViewControllerIdentifier];

的问题

通常，我只是设定 vc.budget = tempbudget如下面的答案所示，但它似乎不了解预算属性。

Answer 1

我会创建一个BaseViewController，其@property类型的对象并以这种方式发送您的对象。

// In your .h
BaseViewController : UIViewController {
}

@property (nonatomic, strong) Budget *budget;

//In your .m
@synthesize budget;

此外，您可以将此行移出if / else语句，因为它是相同的：

vc.budget = tempBudget;
[self.navigationController pushViewController:vc animated:YES];

在推送视图控制器之前设置您的预算属性

使用didSelectRowAtIndexPath传递对象：

1 个答案: