Question

我在谷歌地图表中寻找重复项。问题是纬度略有不同，地址略有不同（但我可以说它们是重复的）。因此，我想得到纬度相同的所有记录，最多小数点后4位。怎么办呢？

类似的东西：

Select * from googlemap
having count(len latitude > 4) > 1

字段：

point_id，entry_id，latitude，longitude，address，city，zipcode，state ，field_id，icon，supplier_id

第一个回答的示例数据：

'9', '51.5124', '9,557,885,908,964,1353,2145,2947'
'17', '32.7921', '17,19,94,2652'
'37', '32.7799', '37,101'
'54', '34.0953', '54,165'
'71', '42.3582', '71,2724'
'73', '25.7660', '73,125'
'100', '25.7906', '100,106'
'112', '25.7870', '112,378'
'113', '32.7114', '113,316'
'114', '25.7689', '114,140'
'129', '25.7708', '129,138,142'
'148', '25.7518', '148,155'
'156', '25.7710', '156,171'
'172', '35.6563', '172,175'
'174', '35.6559', '174,184'
'194', '48.8677', '194,261'
'195', '48.8661', '195,210,248,268'

Answer 1

SELECT *
FROM googlemap g1
INNER JOIN googlemap g2
    ON TRUNCATE(g1.latitude, 4) = TRUNCATE(g2.latitude, 4)
    -- AND TRUNCATE(g1.longitude, 4) = TRUNCATE(g2.longitude, 4)
    AND g1.point_id < g2.point_id

Answer 2

这个怎么样？

SELECT ROUND(latitude,4), GROUP_CONCAT(point_id SEPARATOR ',')
FROM googlemap
GROUP BY ROUND(latitude,4)
HAVING COUNT(*) > 1

查找重复的mysql到数字位数

2 个答案: