Question

当我尝试将HTTP POST响应转换为JSONArray时，我收到错误：

org.json.JSONException：java.lang.String类型的值无法转换为JSONArray

错误发生在行中： JSONArray jArray = new JSONArray（result）;

字符串结果的值是[{“return”：“1”}]，但它在开头包含一个额外的空白字符，当删除时，解决问题。但是，此字符不是空白，因为修剪不能解决问题。我相信POST响应存在一些问题，可能构造不当？（或者POST请求可能是错的？）欢迎任何帮助。

GET请求工作得很好，但我需要做一个POST请求。

这是代码：

HttpPost("usuarioLogin.php",nameValuePairs);
String result = ConvertResponseToString();
try{

    JSONArray jArray = new JSONArray(result);
    JSONObject json_data=null;
    for(int i=0;i<jArray.length();i++){
        json_data = jArray.getJSONObject(i);                
        ret = json_data.getInt("return");   
            retorno = (ret==1)?true:false;
    }               

}
catch(JSONException e1){          
      e1.printStackTrace();       
} catch (ParseException e1) {
    e1.printStackTrace();
}

这是函数HttpPost（）

的代码

private void HttpPost(String php, ArrayList<NameValuePair> nameValuePairs)
{
            try{
                  HttpClient httpclient = new DefaultHttpClient();
                  String host = com.android.taggies.LoginUser.getContext().getResources().getString(R.string.host);
                  HttpPost httppost = new HttpPost("http://"+host+php);
                  httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                  HttpResponse response = httpclient.execute(httppost);
                  HttpEntity entity = response.getEntity();
                  is = entity.getContent();
            }catch(Exception e){
                  Log.e("log_tag", "Error in http connection "+e.toString());
            }
}

这是函数ConvertResponseToString（）

的代码

private String ConvertResponseToString()
{
    //convert response to string
    String result = null;
    try{
        //BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"utf-8"));
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();

        result=sb.toString();
    }
    catch(Exception e){
        Log.e("log_tag", "Error converting result "+e.toString());
    }

    return result;
}

这是我回复POST的php的代码

<?php
mysql_connect("localhost","root","");
mysql_select_db("dbTaggies");

$q=mysql_query("SELECT count(*) as 'return' FROM users
WHERE name='$_POST[user]' AND password ='$_POST[pass]'");

while($e=mysql_fetch_assoc($q))
{
        $output[]=$e;
}       

print(json_encode($output));

mysql_close();
?>

Answer 1

我正在使用这个，对我来说总是很好用：

    DefaultHttpClient client = new DefaultHttpClient();
    JSONObject json = null;
    String resoult = "";
    try
    {
            HttpPost postRequest = new HttpPost("XXXXXXXXXXXXXXXXXX");
            HttpResponse postResponse = client.execute(postRequest);
            HttpEntity postResponseEntity = postResponse.getEntity();
            if (postResponseEntity != null) 
                    resoult= EntityUtils.toString(postResponseEntity);
            json = new JSONObject(resoult);             
    }               
    catch(Exception e)
    {

    }

Answer 2

问题解决了。

PHP文件以UTF-8 WITH BOM保存，解决方案是以UTF8保存文件，没有BOM，并且删除了POST响应中的初始字符。

将HTTP POST响应转换为JSON时出错

2 个答案: