从c#运行MS Access保存的查询

时间:2012-03-27 13:20:07

标签: c# .net-3.5 ms-access-2003

从c#运行查询时,发现MS Access数据库的行为非常奇怪。看来如果MS Access中的查询包含“like”语句,它将不会将其结果返回给Oledb。如果有人知道如何解决这个问题,我将非常感激。 c#代码:

DataTable GetAccessData(string FileName, string Password)
    {
        Query = "select * from [qry_1]";
        DataTable DT = access2dt
            (
            FileName,Password,Query);

        MessageBox.Show(Query);
        if (DT == null || DT.Rows.Count <= 1) throw new Exception("Data not found");
        else return DT;
    }

public static DataTable access2dt(string filename, string password, string query)
{
    string conString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + filename + ";Jet OLEDB:Database Password=" + password;
    OleDbConnection mycon;
    mycon = new OleDbConnection(conString);

    if (mycon.State == ConnectionState.Closed)
    {
        mycon.Open();
    }
    try
    {
        OleDbCommand accessCommand = new OleDbCommand();
        System.Data.DataTable dt = new System.Data.DataTable();
        accessCommand = new OleDbCommand(query, mycon);

        using (OleDbDataReader myReader = accessCommand.ExecuteReader())
        {
            DataTable myTable = new DataTable();
            myTable.Load(myReader);
            return myTable;
        }
    }
    finally
    {
        mycon.Close();
    }

}

MS Access数据库中保存的查询[qry_1]如下所示:

SELECT tbl_MAPPING_GICM_AoA.[Type of expense]
FROM tbl_USGAAP_ALL_TRANS, tbl_MAPPING_GICM_AoA
WHERE tbl_USGAAP_ALL_TRANS.[Account]=[tbl_MAPPING_GICM_AoA].[Natural Account]
AND tbl_USGAAP_ALL_TRANS.[Created By] NOT IN (SELECT [Created by / User ID] FROM tbl_GICM_AoA_EXCL_FACTOR1)
AND tbl_USGAAP_ALL_TRANS.[Je Source] NOT IN (SELECT [JE SOURCE] FROM tbl_GICM_AoA_EXCL_FACTOR2)
AND tbl_USGAAP_ALL_TRANS.[Je Category] NOT IN (SELECT [JE CATEGORY] FROM tbl_GICM_AoA_EXCL_FACTOR3)
AND (tbl_USGAAP_ALL_TRANS.[Account] LIKE '4*' OR tbl_USGAAP_ALL_TRANS.[Account] LIKE '5*'  OR tbl_USGAAP_ALL_TRANS.[Account] LIKE '6*' )

因此,当我在Access中运行它时工作得很好,但是当我从c#调用此查询时,我得到“未找到数据”异常。如果我在查询中删除最后一个字符串(使用LIKE),一切都开始工作

1 个答案:

答案 0 :(得分:6)

尝试替换通配符。 Access使用'*',但使用OLEDB,您需要使用'%'作为通配符。