Question

我在java中通过缓冲区读取器读取一行。线是： abc 3.8229 1.0326 1 1 1.1386 1.006

如何将此行的每个单词存储在字符串数组中？

Answer 1

假设你有

String var = "abc 3.8229 1.0326 1 1 1.1386 1.006";

您可以使用String.split()生成一个String数组。

String[] arr = var.split(" ");

这将产生一个包含arr的每个单词的数组var。

Answer 2

BufferReader br;
...
String line = br.readLine();
String[] words = line.split(" ");

Answer 3

我建议使用扫描仪。

Scanner sc = new Scanner(line);
while( sc.hasNext() ){
    String word = sc.next(); // Get word
}

另外，您还可以使用

方便的方法

double x = sc.nextDouble();
int i = sc.nextInt();

And its ilk.

Answer 4

您可以在从缓冲区读取时拆分单词：

    try {
        String line  = "abc 3.8229 1.0326 1 1 1.1386 1.006";
        List newWordSymbols = Arrays.asList(' ','\n','\r');


        StringReader sr = new StringReader(line);
        List wordList = new ArrayList();
        StringBuilder word = new StringBuilder();
        int ch;
        while (( ch=sr.read())!=-1) {     
            char c = (char)ch;

            if(newWordSymbols.contains(c)){
                wordList.add(word.toString());

                word= new StringBuilder();
            }else{
                word.append(c);
            }

        }
        wordList.add(word.toString());


        System.out.println("Word list ::: "+wordList);
    } catch (IOException ex) {
        ex.printStackTrace();
    }

Answer 5

  import java.io.*;
   class Record
  {
  String name;
  String s1;
  String s2;
  String s3;
  String s4;
   String s5;
  String s6;

  public Record(String name, String s1, String s2, String s3, String s4, String s5,    String s6){
   this.name = name;
   this.s1 = s1;
   this.s2 = s2;
   this.s3 = s3;
   this.s4 = s4;
   this.s5 = s5;
   this.s6 = s6;

}

 public static void main(String args[]){
  try{
   FileInputStream fstream = new FileInputStream("textfile.txt");
      DataInputStream in = new DataInputStream(fstream);
      BufferedReader br = new BufferedReader(new InputStreamReader(in));
      String strLine;
      while ((strLine = br.readLine()) != null)   {
  String[] tokens = str.split(" ");
  Record record = new    Record(tokens[0],tokens[1],tokens[2],tokens[3],tokens[4],tokens[5],tokens[6]);//process  record , etc

 }
 in.close();
  }catch (Exception e){
    System.err.println("Error: " + e.getMessage());
 }
  }
  }

Java Buffer to string array

5 个答案: