与foreach一起

Question

对于使用此代码时的QList，我认为：

QList<Job> jobsList;

jobsList = job.getJobs(650, 654);
QListIterator<Job> iterJobs(jobsList);

while(iterJobs.hasNext())
{
    job = iterJobs.next();
    qDebug() << "IdJob " << job.jobId();
    qDebug() << "jobType " << job.jobType();
}

并且一切都很好，但我怎么能做出预告呢？

非常感谢你

Answer 1

foreach (Job const& job, jobsList) {
  qDebug() << "IdJob " << job.jobId();
  qDebug() << "jobType " << job.jobType();
}

Answer 2

foreach (Job job, jobsList)
{
  qDebug() << "IdJob " << job.jobId();
  qDebug() << "jobType " << job.jobType();
}