我正在关注roseindia的这个知识产生以获得Hibernate的基础知识:“http://roseindia.net/hibernate/hibernate-update.shtml”
我的代码如下所示并获得相同的错误。请帮我修理一下!
Java代码:
public class UpdateExample {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Session sess = null;
try {
SessionFactory fact = new Configuration().configure().buildSessionFactory();
sess = fact.openSession();
Transaction tr = sess.beginTransaction();
Insurance ins = (Insurance)sess.get(Insurance.class, new Long(1));
ins.setInsuranceName("Jivan Dhara");
ins.setInvestementAmount(20000);
ins.setInvestementDate(new Date());
sess.update(ins);
tr.commit();
sess.close();
System.out.println("Update successfully!");
}
catch(Exception e){
System.out.println(e.getMessage());
}
}
}
并且
public class Insurance {
private String insuranceName;
private double investementAmount;
private Date investementDate;
public String getInsuranceName() {
return insuranceName;
}
public void setInsuranceName(String insuranceName) {
this.insuranceName = insuranceName;
}
public double getInvestementAmount() {
return investementAmount;
}
public void setInvestementAmount(double investementAmount) {
this.investementAmount = investementAmount;
}
public Date getInvestementDate() {
return investementDate;
}
public void setInvestementDate(Date investementDate) {
this.investementDate = investementDate;
}
}
我的contact.hbm.xml:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="Contact" table="CONTACT">
<id name="id" type="long" column="ID" >
<generator class="assigned"/>
</id>
<property name="firstName">
<column name="FIRSTNAME" />
</property>
<property name="lastName">
<column name="LASTNAME"/>
</property>
<property name="email">
<column name="EMAIL"/>
</property>
</class>
<class name="Book" table="book">
<id name="lngBookId" type="long" column="id" >
<generator class="increment"/>
</id>
<property name="strBookName">
<column name="bookname" />
</property>
</class>
<class name="Insurance" table="insurance">
<id name="insuranceName" type="String" column="InsuranceName" >
/>
</id>
<property name="investmentAmount">
<column name="InvestmentAmount" />
</property>
<property name="investmentDate">
<column name="InvestmentDate" />
</property>
</class>
</hibernate-mapping>
我得到的错误是:
“读取资源时出错:contact.hbm.xml”
此外,我还使用这些列字段创建了名为Insurance的数据库表。
感谢
斯纳
答案 0 :(得分:0)
hbm.xml文件中是否缺少某些内容?它不是一个完整的XML文件。
您需要将hbm.xml文件与您的类的已编译类文件一起放置。
答案 1 :(得分:0)
这是你的整个.hbm.xml文件吗?如果是这样,它就不完整了 - 它缺少这里显示的正确结构:http://roseindia.net/hibernate/hibernateormapping.shtml
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="roseindia.tutorial.hibernate.Contact" table="CONTACT">
<id name="id" type="long" column="ID" >
<generator class="assigned"/>
</id>
<property name="firstName">
<column name="FIRSTNAME" />
</property>
<property name="lastName">
<column name="LASTNAME"/>
</property>
<property name="email">
<column name="EMAIL"/>
</property>
</class>
</hibernate-mapping>
答案 2 :(得分:0)
你必须定义两个POJO类
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping
PUBLIC "-//Hibernate/Hibernate Mapping DTD//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="Book" table="book" >
<id name="lngBookId" column="id" type="long">
<generator class="increment"></generator>
</id>
<property name="strBookName" type="string">
<column name="bookname" sql-type="VARCHAR2(55)"/>
</property>
</class>
<class name="Insurance" table="insurance" >
<property name="firstName" type="string">
<column name="FIRSTNAME" sql-type="VARCHAR2(55)"/>
</property>
<property name="lastName" type="string">
<column name="LASTNAME" sql-type="VARCHAR2(55)"/>
</property>
<property name="email" type="string">
<column name="EMAIL" sql-type="VARCHAR2(55)"/>
</property>
</class>
</hibernate-mapping>