我有两张桌子。
MainTable:
MainID | LastValue | LastReadingDate
1 | 234 | 01.01.2012
2 | 534 | 03.02.2012
Readings:
MainID | ValueRead | ReadingDate
1 | 123 | 03.02.2012
1 | 488 | 04.03.2012
2 | 324 | 03.02.2012
2 | 683 | 05.04.2012
我想要
SELECT MainTable.MainID, MainTable.LastValue, MainTable.LastReadingDate, (SELECT ValueRead, MAX(ReadingDate)
FROM Readings
WHERE Readings.MainID=MainTable.MainID ORDER BY ValueRead)
换句话说,我想从MainReable获取当前的LastValue和LastReadingDate以及最新的ReadingDate来自ValueRead。
答案 0 :(得分:3)
这是您可以使用的查询。它将显示所有MainTable条目,包括那些尚未包含“阅读”条目的条目。如果您不希望这样,请将LEFT JOIN更改为INNER JOIN。
WITH LastReads AS (
SELECT ROW_NUMBER() OVER (PARTITION BY MainID ORDER BY ReadingDate DESC) AS ReadingNumber,
MainID,
ValueRead,
ReadingDate
FROM Readings
)
SELECT M.MainID, M.LastValue, M.LastReadingDate, R.ValueRead, R.ReadingDate
FROM MainTable M
LEFT OUTER JOIN LastReads R
ON M.MainID = R.MainID
AND R.ReadingNumber = 1 -- Last reading, use 2 or 3 to get the 2nd newest, 3rd newest, etc.
SQLFiddle-link:http://sqlfiddle.com/#!3/16c68/3
另一个链接,每个mainid有N个读数:http://sqlfiddle.com/#!3/16c68/4
答案 1 :(得分:0)
我自己没试过,但是这里有。请尝试
select max(r.readingdate), max(t.lastvalue), max(t.lastreadingdate)
from readings r inner join
( select MainID, LastValue, LastReadingDate
from MainTable m
where LastReadingDate =
(select max(minner.LastReadingDate)
from MainTable minner
where minner.MainID = m.MainID
)
) t
on (r.mainid = t.mainid)
答案 2 :(得分:0)
试试这个:
select M.LastValue, M.LastReadingDate,
(select top 1 ValueRead from Readings where MainID=M.MainID order by ReadingDate desc)
from MainTable M